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maria [59]
3 years ago
13

The boys and girls soccer clubs are fundraising for new uniforms. The boys soccer club is selling candy bars for $2 a piece. The

girls soccer club is selling candles for $4. They must raise more than $800. The girls expect to sell at least 100 candles. Write a system of inequalities to represent the situation
Inequality 1:
Inequality 2:
Mathematics
1 answer:
blondinia [14]3 years ago
6 0

Answer:

2b + 4c = 800

c > 100

Step-by-step explanation:

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*Written Response Question*
belka [17]

The relationship between lines KO and K’O’ is given as Line K'O' = 5 * line KO

<h3>What is a transformation?</h3>

Transformation is the movement of a point from its initial point to a new location. Types of transformation are<em> reflection, rotation, translation and dilation.</em>

Dilation is the increase or decrease in size of a figure by a scale factor.

The larger figure was dilated using a scale factor of 5, hence:

Line K'O' = 5 * line KO

The relationship between lines KO and K’O’ is given as Line K'O' = 5 * line KO

Find out more on transformation at: brainly.com/question/4289712

#SPJ1

7 0
2 years ago
Toss coin 3 times. What is probability of getting 1 head and 2 tails in any order?
Ugo [173]
1/8 because

1/2 x 1/2 x 1/2
7 0
3 years ago
Read 2 more answers
Hello can someone please help me with this.
Zolol [24]

Answer:

if there is equivalent ratio cookies should be 48

3 0
3 years ago
If y varies directly as x and y = 21 when x = 5, find x when y = 42.
Lorico [155]

Answer: 10

<u>Step-by-step explanation:</u>

varies directly means: \frac{y}{x} = k

Step 1: solve for k   ⇒  \frac{21}{5} = k

Step 2: plug in the given value and k to solve for the missing value: \frac{42}{x} = \frac{21}{5}

42(5) = 21(x)

\frac{42(5)}{21} = \frac{21(x)}{21}

2(5) = x

10  = x


5 0
3 years ago
A shipping container will be used to transport several 100-kilogram crates across the country by rail. The greatest weight that
natulia [17]

Answer:

x ≤ 207 crates

Step-by-step explanation:

Greatest weight of the container = 27,500 kilograms

Weight of other shipment = 6,800 kilograms

Weight of a crate = 100 kilograms

Number of 100-kilogram crates that can be loaded into the shipping container = x

The inequality is

27,500 ≤ 6800 + 100x

27,500 - 6800 ≤ 100x

20,700 ≤ 100x

x ≤ 20,700 / 100

x ≤ 207 crates

3 0
3 years ago
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