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forsale [732]
3 years ago
12

The original rectangle has a perimeter of 16

Mathematics
1 answer:
svet-max [94.6K]3 years ago
5 0

12.4 / 6.2 = 2

so other side of enlarged rectangle = 1.8 x 2 = 3.6

Perimeter of enlarged rectangle = 2(3.6 + 12.4) = 32

Answer: 32 feet

------------------------

Another way to do:

12.4 / 6.2 = 2

SF = 2

The original rectangle has a perimeter of 16

Perimeter of the enlarged rectangle = 16 x 2 = 32

Answer: 32 feet

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A student S is suspected of cheating on exam, due to evidence E of cheating being present. Suppose that in the case of a cheatin
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Answer:

Step-by-step explanation:

Suppose we think of an alphabet X to be the Event of the evidence.

Also, if Y be the Event of cheating; &

Y' be the Event of not involved in cheating

From the given information:

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P(\dfrac{X}{Y'}) = 0.01\% = 0.0001

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Thus, P(Y') \ will\ be = 1 - P(Y)

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The probability of cheating & the evidence is present is = P(YX)

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P(YX) =0.6 \times 0.01

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The probabilities of not involved in cheating & the evidence are present is:

P(Y'X) = P(Y')  \times P(\dfrac{X}{Y'})

P(Y'X) = 0.99  \times 0.0001 \\ \\  P(Y'X) = 0.000099

(b)

The required probability that the evidence is present is:

P(YX  or Y'X) = 0.006 + 0.000099

P(YX  or Y'X) = 0.006099

(c)

The required probability that (S) cheat provided the evidence being present is:

Using Bayes Theorem

P(\dfrac{Y}{X}) = \dfrac{P(YX)}{P(Y)}

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3 years ago
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One year had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male pitcher at
lord [1]

Answer:

Thomas had the better year relative to their​ peers.

Step-by-step explanation:

<u>The complete question is</u>: One year Thomas had the lowest ERA​ (earned-run average, mean number of runs yielded per nine innings​ pitched) of any male pitcher at his​ school, with an ERA of 3.31. ​Also, Karla had the lowest ERA of any female pitcher at the school with an ERA of 3.02. For the​ males, the mean ERA was 4.837 and the standard deviation was 0.541. For the​ females, the mean ERA was 4.533 and the standard deviation was 0.539. Find their respective​ z-scores. Which player had the better year relative to their​ peers, or ​? ​(Note: In​ general, the lower the​ ERA, the better the​ pitcher.)

We are given that for the​ males, the mean ERA was 4.837 and the standard deviation was 0.541. For the​ females, the mean ERA was 4.533 and the standard deviation was 0.539.

As, we know that the z-score is calculated by the following formula;

                                 Z  =  \frac{X-\mu}{\sigma} ~ N(0,1)

where, \mu = population mean

           \sigma = standard deviation

Now, firstly we will calculate the z score for Thomas;

z-score = \frac{X-\mu}{\sigma}

            = \frac{3.31-4.837}{0.541}  = -2.823

{Here, the mean ERA for the males was 4.837 and the standard deviation was 0.541}

Similarly, we will calculate the z score for Karla;

z-score = \frac{X-\mu}{\sigma}

            = \frac{3.02-4.533}{0.539}  = -2.807

{Here, the mean ERA for the females was 4.533 and the standard deviation was 0.539}

Now, it is stated in the question that the lower the​ ERA, the better the​ pitcher.

So, we can clearly see that Thomas had a lower ERA of z-score as -2.823 < -2.807. This means that Thomas had the better year relative to their​ peers.

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