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3 years ago

Your friend evaluates the expression when m = 10. is your friend correct? Explain your reasoning.

Mathematics

2 answers:

trapecia [35]3 years ago

7 0

Answer:

yes

Step-by-step explanation:

3 * 10 (m) = 30 so 30 - 6 = 24. 3(10) - 6 is basically the same thing just written different, so it equals 24 too. 3(4) just means 3 times 4 ,which equals 13. Hope that made sense lol

sp2606 [1]3 years ago

4 0

Yes ,

3•10 = 30 - 6 = 24

now when you do 3(4) you get 12 and then subtract the 12 from the 24 and you get 12

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The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown.

omeli [17]

Answer:

The area of one trapezoidal face of the figure is 2 square inches

Step-by-step explanation:

<u><em>The complete question is</em></u>

The point of a square pyramid is cut off, making each lateral face of the pyramid a trapezoid with the dimensions shown. What is the area of one trapezoidal face of the figure?

we know that

The area of a trapezoid is given by the formula

$A=\frac{1}{2}(b_1+b_2)h$

where

b_1 and b-2 are the parallel sides

h is the height of the trapezoid (perpendicular distance between the parallel sides)

we have

$h=1\ in\\b_1=1\ in\\b_2=3\ in$

substitute the given values in the formula

$A=\frac{1}{2}(1+3)(1)$

$A=2\ in^2$

8 0

4 years ago

Read 2 more answers

Write each trigonometric ratio as a fraction in simplest form. show all supporting work

Nesterboy [21]

Answer: $\frac{x}{20}$

Step-by-step explanation:

Sine uses the ratio, $\frac{opposite}{hypotenuse}$ so we can plug in the information we know. since there is no current value for the opposite side of angle A, we can just use a variable to replace it.

$sinA=\frac{x}{20}$

You can't reduce this any further because there is an unknown variable.

7 0

3 years ago

If a = √3-√11 and b = 1 /a, then find a² - b²

Serga [27]

If $b=\frac1a$ , then by rationalizing the denominator we can rewrite

$b = \dfrac1{\sqrt3-\sqrt{11}} \times \dfrac{\sqrt3+\sqrt{11}}{\sqrt3+\sqrt{11}} = \dfrac{\sqrt3+\sqrt{11}}{\left(\sqrt3\right)^2-\left(\sqrt{11}\right)^2} = -\dfrac{\sqrt3+\sqrt{11}}8$