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geniusboy [140]
2 years ago
9

A jar contains 100 coins. If it is very unlikely that you will randomly choose a quarter out of the jar, how many quarters could

be in the jar?
Mathematics
1 answer:
lidiya [134]2 years ago
5 0

Answer:

10

Step-by-step explanation:

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The function f(x)=x^2-12x+5written in vertex form is f(x)=(x-6)^2-31what are the coordinates of the vertex
schepotkina [342]
The vertex to this question is (6, -31)
5 0
3 years ago
AngleB =<br> Round your answer to the nearest hundredth.<br> А<br> 5<br> ?<br> B<br> С<br> 4.
Zarrin [17]

Answer:

B=36.87

Step-by-step explanation:

As we are given the adjacent (a) side and the hypotenuse (h), we can use the cosine function to find the measure of angle B.

Recall that cos(B)=\frac{a}{h}

This means that in order to find B, we need to take the inverse of cosine

This gives us

B=cos^{-1} (\frac{4}{5} )

From a calculator, we find that the answer of this is

B=36.869

When this is rounded to the nearest hundredth, we get

B=36.87

3 0
3 years ago
-30 + 5a &lt; 16<br> A. a 9.2<br> C.<br> a &lt; 9.2<br> a&gt; -2.8<br> a &lt; -2.8
Goryan [66]

Answer:

-30 + 5a < 16

5a < 46

a  <   \frac{46}{5}

a < 9.2

Hope this help...

4 0
2 years ago
Find the distance between the points (-6, – 7) and (5. – 7).
QveST [7]

Answer:

11

Step-by-step explanation:

d=√(5-(-6))²+(-7-(-7))²

d=√(11²+0²)

d=11

5 0
3 years ago
Read 2 more answers
How do you find absolute extrema for a function?<br> f(x)= (8+x)/(8-x); Interval of [4,6]
Mkey [24]
\bf f(x)=\cfrac{8+x}{8-x}\implies \cfrac{dy}{dx}=\stackrel{quotient~rule}{\cfrac{1(8-x)-(8+x)(-1)}{(8-x)^2}}\implies \cfrac{dy}{dx}=\cfrac{16}{(8-x)^2}

now, we get critical points from zeroing out the derivative, and also from zeroing out the denominator, but those at the denominator are critical points where the function is not differentiable, namely a sharp spike or cusp or an asymptote.

so, from zeroing out the derivative we get no critical points there, from the denominator we get x = 8, but can't use it because f(x) is undefined.

therefore, we settle for the endpoints, 4 and 6,

f(4) =3    and      f(6) = 7

doing a first-derivative test, we see the slope just goes up at both points and in between, but the highest is f(6), so the absolute maximum is there, while we can take say f(4) as the only minimum and therefore the absolute minumum as well.
3 0
3 years ago
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