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1 year ago

Find fractional notation 5.6%

1 answer:

6 0

$\begin{gathered} 5.6\text{\%=}\frac{5.6}{100} \\ \Rightarrow\frac{56}{10}\div100 \\ \Rightarrow\frac{56}{10}\times\frac{1}{100} \\ \Rightarrow\frac{56}{1000} \\ Divide\text{ both numerator and denominator by 8, we have:} \\ \frac{7}{125} \end{gathered}$

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Match the fractions with Equivalent percentages

Mrrafil [7]

In order to match each of the pairs you need to divide the numerator by the denominator to make it into a decimal.

Below are the pairs:

21/25 = 84%

13/20 = 65%

2/5 = 40%

3/4 = 75%

3/5 = 60%

7 0

3 years ago

The table shows the average number of pounds of trash generated per person per day in the United States from 1970 to 2010 use th

stepan [7]

Answer: Mean=4.11

Median=4.44

Step-by-step explanation:

Using a graphing calculator, enter the values into the first list. Then run one-variable statistics on the list.

By hand, to find the mean, add together all of the values:

3.25+3.25+3.66+3.83+4.57+4.52+4.74+4.69+4.44 = 36.95

Divide by the total number of data points, 9:

36.95/9 = 4.11

To find the median, order the data from least to greatest:

3.25, 3.25, 3.66, 3.83, 4.44, 4.52, 4.57, 4.69, 4.74

The middle number is 4.44

Mark me as brainliest

5 0

4 years ago

Read 2 more answers

Solve the given inequality :

tigry1 [53]

Answer:

x < -5 or x = 1 or 2 < x < 3 or x > 3

Step-by-step explanation:

Given rational inequality:

$\dfrac{(x-1)^2(x-2)^3}{(x^2-5x+6)^2(x+5)}\geq 0$

$\textsf{Factor }(x^2-5x+6):$

$\implies x^2-2x-3x+6$

$\implies x(x-2)-3(x-2)$

$\implies (x-3)(x-2)$

Therefore:

$\dfrac{(x-1)^2(x-2)^3}{(x-3)^2(x-2)^2(x+5)}\geq 0$

Find the roots by solving f(x) = 0 (set the numerator to zero):

$\implies (x-1)^2(x-2)^3=0$

$\implies (x-1)^2=0\implies x=1$

$\implies (x-2)^3=0 \implies x=2$

Find the restrictions by solving f(x) = undefined (set the denominator to zero):

$\implies (x-3)^2(x-2)^2(x+5)=0$

$\implies (x-3)^2=0 \implies x=3$

$\implies (x-2)^2=0 \implies x=2$

$\implies (x+5)=0 \implies x=-5$

Create a sign chart, using closed dots for the roots and open dots for the restrictions (see attached).

Choose a test value for each region, including one to the left of all the critical values and one to the right of all the critical values.

Test values: -6, 0, 1.5, 2.5, 4

For each test value, determine if the function is positive or negative:

$f(-6)=\dfrac{(-6-1)^2(-6-2)^3}{(-6-3)^2(-6-2)^2(-6+5)}=\dfrac{(+)(-)}{(+)(+)(-)}=+$

$f(0)=\dfrac{(0-1)^2(0-2)^3}{(0-3)^2(0-2)^2(0+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(1.5)=\dfrac{(1.5-1)^2(1.5-2)^3}{(1.5-3)^2(1.5-2)^2(1.5+5)}=\dfrac{(+)(-)}{(+)(+)(+)}=-$

$f(2.5)=\dfrac{(2.5-1)^2(2.5-2)^3}{(2.5-3)^2(2.5-2)^2(2.5+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

$f(4)=\dfrac{(4-1)^2(4-2)^3}{(4-3)^2(4-2)^2(4+5)}=\dfrac{(+)(+)}{(+)(+)(+)}=+$

Record the results on the sign chart for each region (see attached).

As we need to find the values for which f(x) ≥ 0, shade the appropriate regions (zero or positive) on the sign chart (see attached).

Therefore, the solution set is:

x < -5 or x = 1 or 2 < x < 3 or x > 3

As interval notation:

$(- \infty,-5) \cup x=1 \cup (2,3) \cup(3,\infty)$

4 0

2 years ago

Pls answer for brainliest

bagirrra123 [75]

Answer:

135 inches

Step-by-step explanation:

A scale factor is the size of the object on paper.

So to get the actual size we must multiply by the reciprocal of the scale factor.

Dividing by 1/20 is the same as multiplying by 20.

Since the scale is 6.75 (I converted 3/4 to 0.75), we must multiply by 20 to get our original height.

So 6.75 * 20 = 135 inches

6 0

2 years ago

What is the end behavior of the graph of f(x) = x5 – 8x4 + 16x3?

ryzh [129]

Answer:

Step-by-step explanation:

f(x) = x⁵ – 8x⁴ + 16x³

As x approaches +∞, the highest term, x⁵, approaches +∞.

As x approaches -∞, x⁵ approaches -∞ (a negative number raised to an odd exponent is also negative).

Now let's factor:

f(x) = x³ (x² – 8x + 16)

f(x) = x³ (x – 4)²

f(x) has roots at x=0 and x=4. x=4 is a repeated root (because it's squared), so the graph touches the x-axis but does not cross at x=4.

The graph crosses the x-axis at x=0.

7 0

3 years ago

Read 2 more answers