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4vir4ik [10]
2 years ago
6

How many orders are possible to view 6 videos from a stack of 8 videos?

Mathematics
1 answer:
irakobra [83]2 years ago
6 0

Answer:

28

Step-by-step explanation:

We know that ,

  • n C r = n! / ( n - r)! r!

  • 8! / ( 8 - 6)! 6!

  • 8! / 2! × 6!

  • 7 × 8 / 2 × 1

  • 28
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Would I be right if I said 21pi/10 and -pi/10 are two angles coterminal with pi/10?
Anna71 [15]
Two angles are coterminal if they differentiate in a factor of k*(2pi). This is  a multiple of 360 degrees.

In this case 21 [pi /10] = [pi / 10] + 20 [pi/10] = [pi/10] + 2pi, then 21pi/10 is coterminal with pi/10.

In the case of -pi/10 you cannot get to pi/10 by adding a multiple of 2pi , then they are not coternminals.

Conclusion: you would not be right.
7 0
2 years ago
For an integer n ≥ 0, show that (n/2) - (-n/2) = n.<br><br> Use greatest integer function
mars1129 [50]

The greatest integer function returns the largest integer smaller than the number you provide it. That is, if <em>n</em> ≤ <em>x</em> < <em>n</em> + 1, where <em>n</em> is an integer, then the "greatest integer of <em>x</em>" is [<em>x</em>] = <em>n</em>.

• Let <em>n</em> be even. Then we can write <em>n</em> = 2<em>k</em> for some integer <em>k</em> ≥ 0. Now,

[<em>n</em>/2] = [<em>k</em>] = <em>k</em>

while

[-<em>n</em>/2] = [-<em>k</em>] = -<em>k</em>

so that

[<em>n</em>/2] - [-<em>n</em>/2] = 2<em>k</em> = <em>n</em>

<em />

• Let <em>n</em> be odd. Then <em>n</em> = 2<em>k</em> + 1 for some integer <em>k</em> ≥ 0. Every odd integer occurs between two even integers, so that

<em>n</em> - 1 < <em>n</em> < <em>n</em> + 1

or equivalently,

2<em>k</em> < <em>n</em> < 2<em>k</em> + 2

so that

<em>k</em> < <em>n</em>/2 < <em>k</em> + 1

It follows that [<em>n</em>/2] = <em>k</em>.

Similarly, if we negative the previous inequality, we have

-<em>k</em> > -<em>n</em>/2 > -(<em>k</em> + 1), or -<em>k</em> - 1 < -<em>n</em>/2 < -<em>k</em>

which means [-<em>n</em>/2] = -<em>k</em> - 1.

So we make the same conclusion,

[<em>n</em>/2] - [-<em>n</em>/2] = <em>k</em> - (-<em>k</em> - 1) = 2<em>k</em> + 1 = <em>n</em>

3 0
2 years ago
A line segment has endpoint j(2,4) and l(6,8).the point k is the midpoint of jl.what is an equation of a line perpendicular to j
GenaCL600 [577]
The equation of the line is:
 y-yo = m (x-xo)
 Where,
 m = (y2-y1) / (x2-x1)
 Substituting values:
 m = (8-4) / (6-2)
 m = (4) / (4)
 m = 1
 Then, the equation is:
 y-4 = 1 * (x-2)
 Rewriting:
 y = x-2 + 4
 y = x + 2
 The midpoint is:
 k = ((x1 + x2) / 2, (y1 + y2) / 2)
 k = ((2 + 6) / 2, (4 + 8) / 2)
 k = ((8) / 2, (12) / 2)
 k = (4, 6)
 Then, the equation of the perpendicular line that passes through k is:
 y = -x + b
 Looking for b we have:
 6 = -4 + b
 b = 6 + 4
 b = 10
 Substituting:
 y = -x + 10
 Answer:
 An equation of a line perpendicular to jl and passing through k is:
 y = -x + 10
3 0
2 years ago
If f(1)=-10 write the corresponding order pairs
masya89 [10]
F(1)=-10
f(x), so x=1
f(x)=-10, y=f(x), and y=-10
(x,y)=(1,-10)
3 0
3 years ago
If anyone could help answer this question that would be great.
lys-0071 [83]
I believe the answer is 64
First break it off into 2 rectangles on is 4 width and 10 length other is 8 length and 10 width. Then multiple to find area 10•4=40 8•3=24 then add 40+24= 64
3 0
3 years ago
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