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maksim [4K]
3 years ago
10

The value of the function y= (3/5)t decrease by what percentage of t increases by 1 unit

Mathematics
1 answer:
kirza4 [7]3 years ago
7 0

Answer:

Percent of decrease in the value is 40%.

Step-by-step explanation:

Let's find the value of y when t=1 and t=2 because need to find the decrease by percent of t increases by 1 unit.

When t=1

y=\frac{3}{5}^{1}=0.6

When t=2

y=\frac{3}{5} ^{2} =0.36

Percent of decrease = 100 % -\frac{0.36}{0.6}*100%% = 100% -60% =40%

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<u>Corrected Question</u>

Ping lives at the corner of 3rd Street and 6th Avenue. Ari lives at the corner of 21st Street and 18th Avenue. There is a gym 2/3 the distance from Ping's home to Ari's home.  Where is the gym?

  • 9th Street and 10th Avenue
  • 12th Street and 12th Avenue
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Answer:

(D)15th Street and 14th Avenue

Step-by-step explanation:

Ping's Location: (3rd Street, 6th Avenue)

Ari's Location: (21st Street, 18th Avenue)

The gym is at point P which is \dfrac{2}{3} the distance from Ping's home to Ari's home.

That is, Point P divides the line segment in the ratio 2:1.

We use the section formula:

(x,y)=\left(\dfrac{mx_2+nx_1}{m+n}, \dfrac{my_2+ny_1}{m+n}\right)

m:n=2:1, (x_1,y_1)=(3,6), (x_2,y_2)=(21,18)

=\left(\dfrac{2*21+1*2}{2+1}, \dfrac{2*18+1*6}{2+1}\right)\\=\left(\dfrac{45}{3}, \dfrac{42}{3}\right)\\=(15,14)

The gym is located at 15th Street and 14th Avenue.

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