Hey there!
-1.3n = 7.8
First, you have to DIVIDE both sides by -1.3
-1.3n / -1.3 = 7.8 / -1.3
Cancel out: -1.3 / -1.3 because it gives you the value of 1
Keep: 7.8 / -1.3 because it gives us the value of n
7.8 ÷ -1.3 = -6
Thus, n = -6 ✅
Good luck on your assignment and enjoy your day!
~LoveYourselfFirst:)
Answer:
$18,007,50
Step-by-step explanation:
First, you have to calculate the 85% of the base price that the dealer pays for the car:
base price: $18,750
$18,750*85%= $15,937.5
Second, you have to calculate the 75% of the installed options price that the dealer pays:
installed options price= $2,380
$2380*75%= $1,785
Third, you have to add the 85% of the base price plus the 75% of the installed options that the dealer has to pay and you also have to add the destination charge of $285:
$15,937.5+$1,785+$285= $18,007.5
According to this, the dealer has to pay $18,007.5 for the car with a base price of $18,750 and installed options price $2380 including a destination charge of $285.
Answer:
<em>The Graph is shown below</em>
Step-by-step explanation:
<u>The Graph of a Function</u>
Given the function:
It's required to plot the graph of g(x). Let's give x some values:
x={-2,0,2,4,6}
And calculate the values of y:
Point (-2,-24)
Point (0,-6)
Point (2,0)
Point (4,-6)
Point (6,-24)
The graph is shown in the image below
Answer:
The power for the volume of the cube is '3'.
Exponent form of the volume is 
Volume of the cube is 
inch³.
Step-by-step explanation:
We are given,
A cube with side equal to 
inches.
As we know,
Volume of a cube = 
Thus, we get,
Volume of the given cube is,
Volume =
i.e. Volume = inch³
Thus, we have,
The power for the volume of the cube is '3'.
Exponent form of the volume is
Volume of the cube is inch³.
The distance between Car A and car B,When Car A crosses the start line is:
distance =speed car B* time
distance=(15 m/s)(3 s)=45 m
Distance traveled by car A =x, (when the car B is at the same distance from the start line)
time of car A=t
x=10 m/st ⇒ x=10t (1)
Distance traveled by car B=x
time of car B=t-3
x=15(t-3) (2)
With the equations (1) and (2) we make a system of equations:
x=10t
x=15(t-3)
We solve this system of equations:
10t=15(t-3)
10t=15t-45
-5t=-45
t=-45 / -5
t=9
t-3=9-3=6
x=10 t=10 (9)=90
Answer: The time would be 9 seconds for Car A and 6 seconds for car B and the distance would be 90 meters.
