What are the restrictions for y X=10/5+y
1 answer:
Answer:
Step-by-step explanation:
So you have the equation:
. As you may know, you cannot divide by 0, so y has to be restricted in a way that the denominator is never equal to 0. So to find when y makes the denominator 0, simply set the denominator equal to 0, and solve for y. This gives you the equation: 5+y = 0, y=-5. So the y value CANNOT be equal to -5. Because it makes the denominator 0. so
would be the restriction.
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Answer:
x=6, 9, 10, 20, 22, 25, 27, 40 , 48, 59
i= 1, 2 , 3, 4, 5, 6, 7, 8, 9, 10
And as we can see here the position for x=40 is 8, so then we can calculate the percentile for 40 grams like this:
So the the vale of 40 gr correspond to the 80th percentile of the data since accumulates 80% of the values below.
Step-by-step explanation:
We can define a percentile as "a value on a scale of 100 that indicates the percent of a distribution that is equal to or below it"
For this case we have the following data given:
6 , 9, 10, 20, 22, 25, 27, 40 , 48, 59
And we want to calculate the percentile for the value of 40 grams
Since the dataset is on increasing way there is no problem to calculate this percentile.
We see that we have a total of n =10 observations, and we can rank the position of each observation (i) like this:
x=6, 9, 10, 20, 22, 25, 27, 40 , 48, 59
i= 1, 2 , 3, 4, 5, 6, 7, 8, 9, 10
And as we can see here the position for x=40 is 8, so then we can calculate the percentile for 40 grams like this:
So the the vale of 40 gr correspond to the 80th percentile of the data since accumulates 80% of the values below.