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bija089 [108]
2 years ago
11

What are the restrictions for y X=10/5+y

Mathematics
1 answer:
Naya [18.7K]2 years ago
7 0

Answer:

y\ne-5

Step-by-step explanation:

So you have the equation:

  x=\frac{10}{5+y}. As you may know, you cannot divide by 0, so y has to be restricted in a way that the denominator is never equal to 0. So to find when y makes the denominator 0, simply set the denominator equal to 0, and solve for y. This gives you the equation: 5+y = 0, y=-5. So the y value CANNOT be equal to -5. Because it makes the denominator 0. so y\ne-5 would be the restriction.

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aleksandr82 [10.1K]
<span>the correct equation is
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 ax² + bx + c,
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4 years ago
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Step-by-step explanation:

8 0
3 years ago
4 thousands less than 1.895​
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3 years ago
Read 2 more answers
Match each expression in the left column with the correct product in the right column.
lesya692 [45]

Answer:

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Step-by-step explanation:

1) √4 . √-3 . √-3

$ \sqrt{4} = 2 $

$ \sqrt{-3} . \sqrt{-3} = (\sqrt{-3})^2 $

$ \sqrt{4} . (\sqrt{-3})^2 = 2 \times -3 = $ -6

2) √-4 . √-3 . √-3

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Therefore, $ \sqrt{-4} . \sqrt{-3} . \sqrt{-3} = 2. \sqrt{-1}  \times -3 = 2i \times (-3) =  $ - 6i

3) √4 . √3 . √-3

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$ \implies 2 \times 3i = $ 6i

4) √4 . √3 . √3

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$ \sqrt{3} . \sqrt{3} = (\sqrt{3})^2  = 3 $

Therefore, √4 . √3 . √3 = 2 . 3 = 6

5 0
3 years ago
P=R-C<br><br> Solve the formula for C
Anit [1.1K]
P = R - C

R - C = P

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Multiply both sides by - 1

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C = -P + R

C = R - P
 
4 0
3 years ago
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