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2 years ago

See question in attached photo.

Mathematics

2 answers:

mars1129 [50]2 years ago

8 0

I cannot see the photo

KATRIN_1 [288]2 years ago

4 0

Answer:

√-1 or i

Step-by-step explanation:

Since A² = 0 we need to get the value of λ when A = 0:

A = λ*λ - 1(-1) = λ² + 1
A = 0
λ² + 1 = 0 ⇒ λ² = -1 ⇒ λ = √-1 ⇒ λ = i

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My teacher gave us the answers but we just need to show the work for solving the problems. Please help me

Radda [10]

Answer:

Step-by-step explanation:

16x + 22 = 134 ..... because if the two lines are parallel alternative exterior angles are congruent

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3 years ago

The difference between a number and 22 is 57. what is the number

Ksju [112]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

Location is known to affect the number, of a particular item, sold by an auto parts facility. Two different locations, A and B,

Mama L [17]

We have two samples, A and B, so we need to construct a 2 Samp T Int using this formula:

$\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$

In order to use t*, we need to check conditions for using a t-distribution first.

Random for both samples -- NOT STATED in the problem ∴ proceed with caution!
Independence for both samples: 130 < all items sold at Location A; 180 < all items sold at Location B -- we can reasonably assume this is true
Normality: CLT is not met; n < 30 for both locations A and B ∴ proceed with caution!

Since 2/3 conditions aren't met, we can still proceed with the problem but keep in mind that the results will not be as accurate until more data is collected or more information is given in the problem.

Solve for t*:

We need the tail area first.

$\displaystyle \frac{1-.9}{2}= .05$

Next we need the degree of freedom.

The degree of freedom can be found by subtracting the degree of freedom for A and B.

The general formula is df = n - 1.

df for A: 13 - 1 = 12
df for B: 18 - 1 = 17
df for A - B: |12 - 17| = 5

Use a calculator or a t-table to find the corresponding t-score for df = 5 and tail area = .05.

t* = -2.015

Now we can use the formula at the very top to construct a confidence interval for two sample means.

$\overline {x}_A=39$
$s_A=8$
$n_A=13$
$\overline {x}_B = 55$
$s_B=2$
$n_B=18$
$t^{*}=-2.015$

Substitute the variables into the formula: $\displaystyle \overline {x}_1 - \overline {x}_2 \ \pm \ t^{*} \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2} }$ .