The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is (85, 105).
Given
On a coordinate plane, a line is drawn from point K to point J. Point K is at (160, 120) and point J is at (negative 40, 80).
<h3>Coordinates</h3>
The coordinates point any point can be found by using the following formula.

The x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is;

Hence, the x- and y- coordinates of point P on the directed line segment from K to J such that P is Three-fifths the length of the line segment from K to J is (85, 105).
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brainly.com/question/13847533
The answer is 2 x10 = 20
To the power of b which is 15
Answer:
16.34 square inches.
Step-by-step explanation:
Given:
Base of triangle, b = 3 inches
Height of triangle, h = 10.89 inches
Question asked:
What is the area of this triangle in square inches?
Round your answer to the nearest hundredths place .
Solution:
As we know,


As, we have to find the answer to the nearest hundredths place, hence the area of triangle will be 16.34 square inches.
Answer:
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Step-by-step explanation:
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