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mart [117]
3 years ago
5

Since insulin u-100 is 100 units/mL,which of the following shortcuts can be used to convert a dose of u-100 insulin given in uni

ts, to mL
Mathematics
1 answer:
N76 [4]3 years ago
6 0

Answer:

The shortcuts is

     Divide number of units by 100

Step-by-step explanation:

From the question we are told that

  insulin u-100 is  L  =  100 \ unit /mL

 From the data given above we see that

           100 units of  insulin u-100 is contained in  1 mL

So         1 unit of  u-100 is contained in  x mL

=>       x =  \frac{1}{100} \  mL

This means that a unit of  insulin u-100 occupies  x =  \frac{1}{100} \  mL

So we can represent a single unit of insulin u-100 as  \frac{1}{100} \  mL

  Now if 1 unit of insulin u-100 is represented  as    \frac{1}{100} \  mL

Then y unites of   insulin u-100  is represented as  z

So

         z = \frac{y}{100}  \  mL

From the above calculation we can see that the shortcuts to convert  u-100 insulin given in units, to mL is to  divide  number of units by 100

                       

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Find -18 + (-67) Show work.
PtichkaEL [24]

Answer:

- 85

Step-by-step explanation:

-18 - 67= -85

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2 years ago
What is the number to the right of the decimal point called?
koban [17]
Tenths. Hope this helped.
5 0
3 years ago
Two surfers and statistics students collected data on the number of days on which surfers surfed in the last month for 30 longbo
Alisiya [41]

Answer:

Do not reject H0. The mean days surfed for longboarders is significantly larger than the mean days surfed for all shortboarders

Step-by-step explanation:

The null hypothesis is that  the mean days surfed for all long boarders is larger than the mean days surfed for all short boarders

H0:  μL > μs      against the claim Ha:  μL≤ μs

the alternate hypothesis is the mean days surfed for all long boarders isless or equal to  the mean days surfed for all short boarders (because long boards can go out in many different surfing conditions)

The test statistic is

t= x1- x2/  √s1/n1+ s2/n2

1) Calculations

Longboards

Mean

ˉx=∑x/n=4+8+9+4+9+7+9+6+6+11+15+13+16+12+10+12+18+20+15+10+15+19+21+9+22+19+23+13+12+10/30

=377/30

=12.5667

Longboard Variance S2=[∑dx²-(∑dx)²/n]/n-1

=[831-(-13)²/30]/29

=831-5.6333/29

=825.3667/29

=28.4609

Shortboard Mean

ˉx=∑x/n=6+4+6+6+7+7+7+10+4+6+7+5+8+9+4+15+13+9+12+11+12+13+9+11+13+15+9+19+20+11/30

=288/30

=9.6

Shortboard Variance S2=[∑x²-(∑x)²/n]/n-1

=[ 3270-(288)2/30]/29

=3270-2764.8/29

=505.2/29

=17.4207

2) Putting values in the test statistic

t=|x1-x2|/√S²1/n1+S²2/n2

t =|12.5667-9.6|/√28.4609/30+17.4207/30

t =|2.9667|/√0.9487+0.5807

t=|2.9667|/√1.5294

t=|2.9667|/1.2367

t=2.3989

3) Degree of freedom =n1+n2-2=30+30-2=58

4) The critical region is t ≤ t(0.05) (58) =1.6716

5) Since the calculated t= 2.4 does not fall in the critical region t(0.05) (58)  ≤ 1.6716 we do not reject H0.

The p-value is 0.008969. The result is significant at p <0 .05.

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Therefore circumference is as follows
C = 2^_r

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<span>social learning

</span>If your little sister watches you and tries to copy everything you do, she is exhibiting which type of learning?
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insightful learning
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