2.4 is the answer to this question
Simple....
you have:
4x+3y≤-12
To solve for X or Y just isolate the variable....
4x+3y≤-12
-3y -3y
4x≤-3y-12
Now divide by 4....
![\frac{4x}{4} \leq \frac{-3y-12}{4}](https://tex.z-dn.net/?f=%20%5Cfrac%7B4x%7D%7B4%7D%20%20%5Cleq%20%20%5Cfrac%7B-3y-12%7D%7B4%7D%20)
![x \leq -\frac{3y}{4} -3](https://tex.z-dn.net/?f=x%20%5Cleq%20%20-%5Cfrac%7B3y%7D%7B4%7D%20-3)
Now for y:
4x+3y≤-12
4x+3y≤-12
-4x -4x
3y≤-4x-12
Divide by 3...
![\frac{3y}{3} \leq \frac{-4x-12}{3}](https://tex.z-dn.net/?f=%20%5Cfrac%7B3y%7D%7B3%7D%20%20%5Cleq%20%20%5Cfrac%7B-4x-12%7D%7B3%7D%20)
![y \leq -\frac{4x}{3} -4](https://tex.z-dn.net/?f=y%20%5Cleq%20%20-%5Cfrac%7B4x%7D%7B3%7D%20-4)
This is the way to solve it.
Thus, your answer.
Answer:
en qué grado estas bueno si me entiendes xq yo no hablo inglés
Answer:
b dancers because I said to be