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lidiya [134]
3 years ago
15

Okay so I'm working on solving equations

" id="TexFormula1" title=" - 15x + 5 = - 10x + 25" alt=" - 15x + 5 = - 10x + 25" align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Ksenya-84 [330]3 years ago
8 0

Answer:

x = -4

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Equality Properties

Step-by-step explanation:

<u>Step 1: Define</u>

-15x + 5 = -10x + 25

<u>Step 2: Solve for </u><em><u>x</u></em>

  1. Add 15x on both sides:                    5 = 5x + 25
  2. Subtract 25 on both sides:              -20 = 5x
  3. Divide 5 on both sides:                   -4 = x
  4. Rewrite:                                             x = -4
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Debora [2.8K]

By descriptive method = Set A is a set of all natural numbers between 5 and 50 which gives remainder 3 when divided by 8.Listing method : A = { 11, 19, 27, 35, 43} and Set builder method : A = { x : x ∈ N, x = 8 c + 3 and 1 < c < 5

We are given that:

Number range 5 - 50

Remainder = 3 when the number is divided by 8

We need to find the sets of numbers between 5 to 50 when they are divided by 8 gives remainder 3 by description method, listing method and set builder method.

Let the set be A

Descriptive Method

Set A is a set of all natural numbers between 5 and 50 which gives remainder 3 when divided by 8.

Listing Method

A = { 11, 19, 27, 35, 43}

Set Builder Method

A = { x : x ∈ N, x = 8 c + 3 and 1 < c < 5

Therefore, we get that, by descriptive method = Set A is a set of all natural numbers between 5 and 50 which gives remainder 3 when divided by 8.Listing method : A = { 11, 19, 27, 35, 43} and Set builder method : A = { x : x ∈ N, x = 8 c + 3 and 1 < c < 5

#SPJ9

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2 years ago
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