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2 years ago

If John had 3 apples and Gave Jamal 2 how much left after you multiple by 6???

Mathematics

1 answer:

goldfiish [28.3K]2 years ago

8 0

Answer:

6 apples

Step-by-step explanation:

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Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

SIZIF [17.4K]

C = 4M + 5
4M = C - 5
M = (C - 5)/4

answer is D. Last one.

6 0

3 years ago

What is the least common multiple of 2, 3, and 10?

Musya8 [376]

Answer:

Step-by-step explanation:

3 0

2 years ago

The formula for the nth term of the arithmetic sequence first term is 9 common difference is -2

Yanka [14]

Answer:

$a_n = 9 - 2(n-1)$

Step-by-step explanation:

Arithmetic sequence:

In an arithmetic sequence, the difference between consecutive terms is always the same, and is called common difference.

The nth term is given by the following equation:

$a_n = a_1 + (n-1)d$

In which $a_1$ is the first term and d is the common difference.

First term is 9 common difference is -2

This means that $a_1 = 9, d = -2$

So, the nth term is given by:

$a_n = a_1 + (n-1)d$

$a_n = 9 + (n-1)(-2)$

$a_n = 9 - 2(n-1)$

3 0

3 years ago

Use Stokes' Theorem to evaluate C F · dr F(x, y, z) = xyi + yzj + zxk, C is the boundary of the part of the paraboloid z = 1 − x

Serggg [28]

I assume $C$ has counterclockwise orientation when viewed from above.

By Stokes' theorem,

$\displaystyle\int_C\vec F\cdot\mathrm d\vec r=\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

so we first compute the curl:

$\vec F(x,y,z)=xy\,\vec\imath+yz\,\vec\jmath+xz\,\vec k$

$\implies\nabla\times\vec F(x,y,z)=-y\,\vec\imath-z\,\vec\jmath-x\,\vec k$

Then parameterize $S$ by

$\vec r(u,v)=\cos u\sin v\,\vec\imath+\sin u\sin v\,\vec\jmath+\cos^2v\,\vec k$

where the $z$ -component is obtained from

$1-(\cos u\sin v)^2-(\sin u\sin v)^2=1-\sin^2v=\cos^2v$

with $0\le u\le\dfrac\pi2$ and $0\le v\le\dfrac\pi2$ .

Take the normal vector to $S$ to be

$\vec r_v\times\vec r_u=2\cos u\cos v\sin^2v\,\vec\imath+\sin u\sin v\sin(2v)\,\vec\jmath+\cos v\sin v\,\vec k$

Then the line integral is equal in value to the surface integral,

$\displaystyle\iint_S(\nabla\times\vec F)\cdot\mathrm d\vec S$

$=\displaystyle\int_0^{\pi/2}\int_0^{\pi/2}(-\sin u\sin v\,\vec\imath-\cos^2v\,\vec\jmath-\cos u\sin v\,\vec k)\cdot(\vec r_v\times\vec r_u)\,\mathrm du\,\mathrm dv$

$=\displaystyle-\int_0^{\pi/2}\int_0^{\pi/2}\cos v\sin^2v(\cos u+2\cos^2v\sin u+\sin(2u)\sin v)\,\mathrm du\,\mathrm dv=\boxed{-\frac{17}{20}}$

6 0

3 years ago

Cost price = 40

Helen [10]

Answer:

c=40

s=52

s<c

40 -52

8(eight)

8 0

3 years ago

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