All categories

3 years ago

What is the value of x+y

Mathematics

2 answers:

stiks02 [169]3 years ago

6 0

Answer:

your answer is (3,9)

Step-by-step explanation:

nirvana33 [79]3 years ago

5 0

Answer:

x+y=12

Step-by-step explanation:

You might be interested in

Find the perimeter of the image below

Naily [24]

Answer:

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Solve the inequality -d ≥ 0.5

Mariulka [41]

Answer:

d ≤ -0.5

Step-by-step explanation:

Multiply each term by -1

8 0

3 years ago

What are the ratios of sine, cosine, and tangent for angle Y? sin(Y) = StartFraction X Z Over X Y EndFraction; cos(Y) = StartFra

Sholpan [36]

Answer:

$\sin Y= \frac{XZ}{XY}$

$\cos Y= \frac{YZ}{XY}$

$\tan Y= \frac{XZ}{YZ}$

Step-by-step explanation:

Given

See attachment for triangle

Required

Find $\sin, \cos$ and $\tan$ of angle Y

For angle Y:

$Opposite = XZ$

$Adjacent = YZ$

$Hypotenuse = XY$

The $\sin$ of an angle is calculated as:

$\sin\theta = \frac{Opposite}{Hypotenuse}$

So:

$\sin Y= \frac{XZ}{XY}$

The $\cos$ of an angle is calculated as:

$\cos\theta = \frac{Adjacent}{Hypotenuse}$

So:

$\cos Y= \frac{YZ}{XY}$

The $\tan$ of an angle is calculated as:

$\tan\theta = \frac{Opposite}{Adjacent}$

So:

$\tan Y= \frac{XZ}{YZ}$

7 0

3 years ago

Read 2 more answers

Find the distance between the points (13,20) and (18,8)

steposvetlana [31]

Answer:

(5,12)

Step-by-step explanation:

because 18-13=5 and 20-8=12

5 0

4 years ago

Read 2 more answers

For which rational expression is 8 an excluded value ? check all that apply

denis23 [38]

<u>Answer:</u>

The correct answer options are C. $\frac{x^2+5}{x-8}$ and D. $\frac{x^2-x-56}{x^2-64}$ .

<u>Step-by-step explanation:</u>

The values which make the denominator equal to zero are called the excluded values.

Here, we can substitute 8 for x and check if it makes the denominator 0.

$\frac{x-8}{x+8} = \frac{8-8}{8+8} =\frac{0}{16} =0$

$\frac{x-2}{x^2-4} = \frac{8-2}{8^2-4} =\frac{6}{60} =\frac{1}{10}$

$\frac{x^2+5}{x-8} = \frac{8^2+5}{8-8} =\frac{69}{0}$

$\frac{x^2-x-56}{x^2-64} = \frac{8^2-8-56}{8^2-64} = \frac{0}{0} =0$

$\frac{8x^2-2}{x^2-16} = \frac{8(8)^2-2}{8^2-16} =\frac{510}{48}$

7 0

3 years ago