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OverLord2011 [107]
3 years ago
7

A tractor travels at an average speed of 36km/hr for 10 sec.calculate the distance the tractor covers in 10 sec​

Mathematics
2 answers:
Katen [24]3 years ago
8 0

1 hour = 3600 seconds

10 seconds is 10/3600 = 1/360 of an hour

36 km per hour x 1/360 of an hour = 0.1 km (100 meters)

DIA [1.3K]3 years ago
5 0

Answer:

.1km

Step-by-step explanation:

The tractor can move .01 km in a second so 10 times .01 is .1

so the tractor can move .1km every 10 seconds

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Which of the following is equivalent to 3(x + 5) - 6 ?
Fynjy0 [20]

Answer:

3x5 is 15, 15-6 is 9

Step-by-step explanation:

6 0
3 years ago
2 Points
LiRa [457]

Answer:

6c

Step-by-step explanation:

If the mean of the values in a data set is c, and each of the values in the data set

were multiplied by 6, the mean of the resulting data is 6c.

The reason is that, the number that multiplies all the data set can be factored and it becomes a multiplier of the mean of the original data set.

k\bar  x =k  \frac{ \sum \: x}{n}

Therefore the new mean is 6c

3 0
3 years ago
Evaluate the integral following ​
alina1380 [7]

Answer:

\displaystyle{4\tan x + \sin 2x - 6x + C}

Step-by-step explanation:

We are given the integral of:

\displaystyle{\int 4(\sec x - \cos x)^2 \, dx}

First, we can use a property to separate a constant out of integrand:

\displaystyle{4 \int (\sec x - \cos x)^2 \, dx}

Next, expand the expression (integrand):

\displaystyle{4 \int \sec^2 x - 2\sec x \cos x + \cos^2 x \, dx}

Since \displaystyle{\sec x = \dfrac{1}{\cos x}} then it can be simplified to:

\displaystyle{4 \int \dfrac{1}{\cos^2 x} - 2\dfrac{1}{\cos x} \cos x + \cos^2 x \, dx}\\\\\displaystyle{4 \int \dfrac{1}{\cos^2 x} - 2 + \cos^2 x \, dx}

Recall the formula:

\displaystyle{\int \dfrac{1}{\cos ^2 x} \, dx = \int \sec ^2 x \, dx = \tan x + C}\\\\\displaystyle{\int A \, dx = Ax + C \ \ \tt{(A \ and \ C \ are \ constant.)}

For \displaystyle{\cos ^2 x}, we need to convert to another identity since the integrand does not have a default or specific integration formula. We know that:

\displaystyle{2\cos^2 x -1 = \cos2x}

We can solve for \displaystyle{\cos ^2x} which is:

\displaystyle{2\cos^2 x = \cos2x+1}\\\\\displaystyle{\cos^2x = \dfrac{\cos 2x +1}{2}}

Therefore, we can write new integral as:

\displaystyle{4 \int \dfrac{1}{\cos^2 x} - 2 + \dfrac{\cos2x +1}{2} \, dx}

Evaluate each integral, applying the integration formula:

\displaystyle{\int \dfrac{1}{\cos^2x} \, dx = \boxed{\tan x + C}}\\\\\displaystyle{\int -2 \, dx = \boxed{-2x + C}}\\\\\displaystyle{\int \dfrac{\cos 2x +1}{2} \, dx = \dfrac{1}{2}\int \cos 2x +1 \, dx}\\\\\displaystyle{= \dfrac{1}{2}\left(\dfrac{1}{2}\sin 2x + x\right) + C}\\\\\displaystyle{= \boxed{\dfrac{1}{4}\sin 2x + \dfrac{1}{2}x + C}}

Then add all these boxed integrated together then we'll get:

\displaystyle{4\left(\tan x - 2x + \dfrac{1}{4}\sin 2x + \dfrac{1}{2} x\right) + C}

Expand 4 in the expression:

\displaystyle{4\tan x - 8x +\sin 2x + 2 x + C}\\\\\displaystyle{4\tan x + \sin 2x - 6x + C}

Therefore, the answer is:

\displaystyle{4\tan x + \sin 2x - 6x + C}

4 0
1 year ago
Please answer I’ll make you brainlienst!
natali 33 [55]

Answer:

the answer is -2 by looking at the question

7 0
4 years ago
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Question 18(Multiple Choice Worth 2 points)
AleksandrR [38]

Answer: 5.8 and 6.

hope this helps

4 0
3 years ago
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