Answer:
3
Step-by-step explanation:
Half-life = [elapsed time * log (2)] / [log (begng amt / endg amt)]
half-life = (3 days * 0.30102999566) / log (1 / .58)
<span>half-life = 0.903089987 / log </span>
(<span>
<span>
<span>
1.724137931)
</span></span></span>half-life = <span>0.903089987 / 0.23657200643</span>
half-life =
<span>
<span>
<span>
3.8174 days
Source:
http://www.1728.org/halflife.htm
</span></span></span>
<span>x−38.45=17.71 is your answer
</span>
Answer:
it's C: It is the graph of y = log2x translated 9 units down and 3 units to the left.
<span>The word problem gives a rate of oil consumption at a rate of 25 gallons per 3 hours and 45 minutes. 3 hours and 45 minutes can be displayed as 3.75 hours. so you can say the generator consumes oil at a rate of 25 gallons per 3.75 hours. The following equation give you the oil consumption on a per hour basis; 25/3.75 and that gives you 6.67 gallons per hour. In 6 hours the generator will consume 40 gallons.</span>
