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1 year ago

Original price of a cd is 12.50. what is the price with a discount of 39%

Mathematics

1 answer:

vredina [299]1 year ago

6 0

Answer:

original price of a cd is 12.50. what is the price with a discount of 39%

Step-by-step explanation:

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Use the inverse function-inverse cofunction

vivado [14]

Answer:

$arccot(x)'=-\frac{1}{1+x^2}$

Step-by-step explanation:

<u>Use implicit differentiation:</u>

$y=arccot(x)$

$cot(y)=x$

$\frac{1}{tan(y)}=x$

$\frac{cos(y)}{sin(y)}=x$

$\frac{dy}{dx}(\frac{cos(y)}{sin(y)})=\frac{dy}{dx}(x)$

$\frac{sin(y)(-sin(y))-cos(y)cos(y)}{sin^2(y)}*\frac{dy}{dx}=1$ (Quotient Rule: $\frac{d}{dx}(\frac{f(x)}{g(x)})=\frac{g(x)f'(x)-f(x)g'(x)}{(g(x))^2}$ )

$\frac{-sin^2(y)-cos^2(y)}{sin^2(y)}*\frac{dy}{dx}=1$

$\frac{-(sin^2(y)+cos^2(y))}{sin^2(y)}*\frac{dy}{dx}=1$

$\frac{-1}{sin^2(y)}*\frac{dy}{dx}=1$

$-csc^2(y)\frac{dy}{dx}=1$

$\frac{dy}{dx}=\frac{1}{-csc^2(y)}$

$\frac{dy}{dx}=-sin^2(y)$

$\frac{dy}{dx}=-sin^2(arccot(x))$

See the attached picture to understand how to evaluate the mixed composition of trig functions using a right triangle.

Therefore, the derivative of arccot(x) is $-\frac{1}{\sqrt{1+x^2}}$ .

4 0

1 year ago

A recent national survey found that high school students watched an average (mean) of 7.1 movies per month with a population sta

muminat

Answer:

H0: μc ≤ μs Ha :μc > μs

Step-by-step explanation:

The null and alternate hypotheses can be stated as

H0: μc ≤ μs Ha :μc > μs one tailed test

Where

μc = Mean of college students watching movies in a month

μs = Mean of school students watching movies in a month

For one tailed test of α =0.05 the value of Z= ± 1.645

The critical region will be Z > ± 1.645

It is of importance to note that by rejecting the null hypothesis and accepting the alternate hypothesis we are automatically rejecting all values of mean that are greater than 7.1

3 0

2 years ago

V=1/3πh^2 (3r-h) solve for r

stellarik [79]

R=1v+h([pi]h^2) all over 3

5 0

2 years ago

I need some help please

AleksandrR [38]

Answer:

gimme points

Step-by-step explanation:

8 0

2 years ago

Sketch a graph that is discrete, has a maximum, does not pass through the origin, and is an absolute value function

Stella [2.4K]

Um.. I can't sketch a graph on here.
A discrete function can't be an absolute value function because an absolute value function is continuous. But, the function equation can be as simple as
f(x) = - | x + 1 |
Just don't connect the dots when you draw it and boom, you're done.

6 0

2 years ago