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DiKsa [7]
3 years ago
13

Which group contains numbers that all round most closely to 0?

Mathematics
1 answer:
velikii [3]3 years ago
7 0

Answer:

1/5, 2/9, 0/4

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Twice a number is one?
Law Incorporation [45]

Answer:

2x=1

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
Solving systems by Substitution Homework y=x+4 y=x-3​
zvonat [6]
There is no solution for this equation since they have the same slope, x/1. The only difference between these two is that their y intercepts are different meaning that they will be parallel lines that will never intersect among one other. For example, think of it as two separate lines that are have the same slope and never gain more distance/units from one another.


Solve:

To solve, you have to get one of this equations into a Ax+By=C equation form, standard equation. Let’s change y=x+4 into a standard equation.

We have to get x and y together and 4 as C.
So let’s subtract x from both sides;

y=x+4
-x -x
————————
-x+y=4

This is a standard equation.

Now let’s substitute.

take the standard equation and plug in y which is x+4 since there is a equation meaning it’s y=x+4


-x+(x+4)=4


Let’s simplify this mess.


-x+x equals 0. So we are left with 4=4.

Subtract 4 from both sides and we get 0=0



This means there is no solution. Hoped this helped.
8 0
3 years ago
I need this question for unit test
krek1111 [17]
The answer is this:
A. (6,3)
3 0
3 years ago
Pleaseeeeee graph the following
irina [24]

Answer:

<h3>Hope it helps...</h3><h3>have a great day/night</h3>

8 0
3 years ago
Giá trị x thoả mãn x(x − 3) + x − 3 =0 là
svet-max [94.6K]

Here we will use the trial and error method.

  • We will try putting different values of x.
<h3 /><h3>1st of all</h3><h3>x=1</h3>

\begin{gathered}\\ \sf\longmapsto 1(1-3)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto (-2)+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+1-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2-2=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -4≠0\end{gathered}

<h2>Now,</h2><h3>x=2</h3>

\begin{gathered}\\ \sf\longmapsto 2(2-3)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 2(-1)+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -2+2-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto -3≠0\end{gathered}

<h2>Again,</h2><h3>x=3</h3>

\begin{gathered}\\ \sf\longmapsto 3(3-3)+3-3=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3(3-3)=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 3×0=0\end{gathered}

\begin{gathered}\\ \sf\longmapsto 0=0\end{gathered}

<h3>☣Hence, The value of X as 3 satisfies the equation!</h3>
5 0
3 years ago
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