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Arada [10]
3 years ago
10

Find the 5th derivative by using calculus with full workings of 7g^8+2g^7+4g^6+3g^5+g^2+5g+276.3

Mathematics
1 answer:
enot [183]3 years ago
8 0

This is an exercise in applying the power rule, which says

f(x) = x^n \implies f'(x) = nx^{n-1}

Starting with

7g^8 + 2g^7 + 4g^6 + 3g^5 + g^2 + 5g + 276.3

we have

• first derivative

56g^7 + 14g^6 + 24g^5 + 15g^4 + 2g + 5

• second derivative

392g^6 + 84g^5 + 120g^4 + 60g^3 + 2

• third derivative

2352g^5 + 420g^4 + 480g^3 + 180g^2

• fourth derivative

11760g^4 + 1680g^3 + 1440g^2 + 360g

• fifth derivative

\boxed{47040g^3 + 5040g^2 + 2880g + 360}

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