The new information implies that the number of hot dogs is 1 and the bags of chips is 2
<h3>The system of equations</h3>
The statements are given as:
<em>“Sell a hot dog and chips for $3, or sell four hot dogs and four bags of chips for $10.</em>
<em />
Represent the hot dog with x and the chips with y.
So, we have
x + y = 3
4x + 4y = 10
<h3>How to solve the system of equations</h3>
In (a), we have:
x + y = 3
4x + 4y = 10
Multiply the first equation by 4
4x + 4y = 12
Subtract this equation from the second equation
4x - 4x + 4y - 4y = 12 - 10
Evaluate
0 = 2
The above equation is false.
This means that the system of equations has no solution
<h3>What does that do for your system of equations now?</h3>
The second statement is given as:
"sell four hot dogs and two bags of chips for $10.”
So, we have the following system of equations:
x + y = 3
4x + 2y = 10
Make x the subject in x + y = 3
x = 3 - y
Substitute x = 3 - y in 4x + 2y = 10
4(3 - y) + 2y = 10
Expand the bracket
12 - 4y + 2y = 10
Evaluate the like terms
2y = 2
Divide by 2
y = 1
Substitute y = 1 in x = 3 - y
x = 3 - 1
Evaluate
x = 2
Hence, the new information implies that the number of hot dogs is 1 and the bags of chips is 2
Read more about system of equations at:
brainly.com/question/13729904
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