Answer:
y=t−1+ce
−t
where t=tanx.
Given, cos
2
x
dx
dy
+y=tanx
⇒
dx
dy
+ysec
2
x=tanxsec
2
x ....(1)
Here P=sec
2
x⇒∫PdP=∫sec
2
xdx=tanx
∴I.F.=e
tanx
Multiplying (1) by I.F. we get
e
tanx
dx
dy
+e
tanx
ysec
2
x=e
tanx
tanxsec
2
x
Integrating both sides, we get
ye
tanx
=∫e
tanx
.tanxsec
2
xdx
Put tanx=t⇒sec
2
xdx=dt
∴ye
t
=∫te
t
dt=e
t
(t−1)+c
⇒y=t−1+ce
−t
where t=tanx
Answer:
113.04 cm.
Step-by-step explanation:
Step 1: <u>Formula/explain</u>
To find the area of a circle, multiply the radius by itself twice, then multiply the product pi.
Step 2: <u>Solve</u>
According to the word problem, the circle has a diameter of 12. This means it has a radius of 6.
Now, we plug the numbers into formula.
Step 3: <u>Conclude</u>
Therefore, the area of this circle is 113.04 cm.
Answer: 1 = y
All you have to do is carry the 2 over and subtract it from 6 so then you just have 4=4y which will turn into 1=y
26 = 3x - 2 - 7x
26 + 2 = -4x
28 / -4 = x
x = -7
Best answer me please!