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Anastaziya [24]

3 years ago

9

Which point is located at (2, 6)? On a coordinate plane, point A is 6 units to the right and 2 units up. Point B is 6 units to t

he left and 2 units up. Point C is 2 units to the right and 6 units up. Point D is 2 units to the left and 6 units up. A B C D

2 answers:

yKpoI14uk [10]3 years ago

7 0

Answer:

point c

Step-by-step explanation:

kow [346]3 years ago

6 0

Point C

Ignore - babbucebuc

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The area of a rectangle is 65 m2 , and the length of the rectangle is 3 m less than twice the width. find the dimensions of the

salantis [7]

X = <span>width
2x-3 = </span><span>length

</span> $x(2x-3) = 65\\
2x^2 - 3x - 65 = 0 \\ D=b^2-4ac=(-3)^2-4*2*(-65)=529\\
x_{1,2}= \frac{-bб \sqrt{D} }{2a}= \frac{3б 23}{4} \\ x_1=-5 \ \ \O \\ x_2=6.5 \ \$

width = 6.5 m
length = 2x-3 = 2*6.5 - 3 = 10 m

4 0

3 years ago

Determine the value of x in the figure below.<br><br> x =

Marianna [84]

Answer:

116

Step-by-step explanation:

16+16=56/2=4

5 0

2 years ago

If you rearrange the equation so w is the independent variable, then what is u?<br><br> -2u+6w=9

Serjik [45]

Answer:

u = - ( 9-6w)/2

Step-by-step explanation:

to evaluate for u in the expression -2u+6w=9 is simply to look for a way such that we would express u in terms of w and other variables.

solution

-2u+6w=9

-2u = 9 - 6w

divide both sides by the coefficient of u which is -2

-2u/u = 9 - 6w/-2

u = - ( 9-6w)/2

therefore the value of u when rearranged in the equation -2u+6w=9 is evaluated to be equals to

u = - ( 9-6w)/2

7 0

3 years ago

1011+111 in binary form

Ann [662]

Answer:

10010

Step-by-step explanation:

$1011=1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$111=1(2)^2+1(2)^1+1(2)^0$

So $1011+111$ gives us:

$1(2)^3+0(2)^2+1(2)^1+1(2)^0$

$+$

$1(2)^2+1(2)^1+1(2)^0$

-----------------------------------------------------

Combine like terms:

$1(2)^3+(0+1)(2)^2+(1+1)(2)^1+(1+1)(2)^0$

$1(2)^3+1(2)^2+(2)(2)^1+(2)(2)^0$

We aren't allowed to have a coefficient bigger than 1.

I'm going to replace $2^0$ with 1 and $2$ with $(2)^1$ :

$1(2)^3+1(2)^2+(2)^2+(2)^1(1)$

I want a $2^0$ number:

$1(2)^3+1(2)^2+1(2)^2+1(2)^1+0(2)^0$

Combine like terms:

$1(2)^3+2(2)^2+1(2)^1+0(2)^0$

$2(2)^2=2^3$ :

$1(2)^3+2^3+1(2)^1+0(2)^0$

Combine like terms:

$2(2)^3+1(2)^1+0(2)^0$

We can rewrite the first term by law of exponents:

$2^4+1(2)^1+0(2)^0$

$1(2)^4+1(2)^1+0(2)^0$

So the binary form is:

$10010$

Maybe you like this way more:

Keep in mind 1+1=10 and that 1+1+1=11:

Setup:

1 0 1 1

+ 1 1 1

------------------------------

(1) (1) (1)

1 0 1 1

+ 1 1 1

------------------------------

1 0 0 1 0

I had to do some carry over with my 1+1=10 and 1+1+1=11.

8 0

3 years ago

Please help me, picture below.

Lesechka [4]

The answer is the last one, 8 square root 6 because when factoring out 486 you will get 9 square root 6. When factoring out 24, you will get 2 square root 6 and the 6 is already factored out. After that you add and subtract and you will get the last answer 8 square root 6. Hope that helped.

8 0

3 years ago