for the given A.P
5,9,13,...
First term (a)=5
common difference (d) = 9-5=4
Let Tn=2012
a +(n-1) d=2012
5 +(n-1) 4=2012
(n-1) 4=2012-5
(n-1)4=2007
n-1=501.75
n=1+501.75
n=502.75 -- - - - - -> which is not possible.
No.of terms can never in fraction.
Hence, 2012 is not a term of given A.P
252 miles overall.
To find this, I took the 292 average for 4 days and multiplied it by 4. I also took the 220 mile average for 5 days and multiplied it by 5. I then added these two numbers and I got 2268 miles. In order to find the average, I divided the 2268 miles by the 9 total days.
Suppose that a large mixing tank initially holds 300 gallons of water is which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min. If the concentration of the solution entering is 2 lb/gal, determine a differential equation for the amount of salt A(t) in the tank at time t.
6 tenths or 6/10
it doesn't matter how many zeros you have after the .6 it's still 6 tenths. It can have a hundred zeros it will still be just .6 = 6/10 = 6 tenths
Hope that helps you. :-)
