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Tom [10]
2 years ago
15

Suppose that a large mixing tank initially holds 300 gallons of water is which 50 pounds of salt have been dissolved. Another br

ine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min. If the concentration of the solution entering is 2 lb/gal, determine a differential equation for the amount of salt A(t) in the tank at time t.
Mathematics
1 answer:
Law Incorporation [45]2 years ago
3 0

Suppose that a large mixing tank initially holds 300 gallons of water is which 50 pounds of salt have been dissolved. Another brine solution is pumped into the tank at a rate of 3 gal/min, and when the solution is well stirred, it is then pumped out at a slower rate of 2 gal/min. If the concentration of the solution entering is 2 lb/gal, determine a differential equation for the amount of salt A(t) in the tank at time t.

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Step-by-step explanation:

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Y=5x+2 <br> 4x-y=0<br> is (2,12) a solution of the system?
Svetach [21]

Answer:

The point (2,12) is not a solution of the system

see the explanation

Step-by-step explanation:

we have

y=5x+2 ----> equation A

4x-y=0 ----> equation B

Solve the system by elimination

Adds equation A and equation B

y=5x+2\\4x-y=0\\------\\y+4x-y=5x+2+0\\4x=5x+2\\5x-4x=-2\\x=-2

Find the value of y

substitute the value of x in the equation A

y=5(-2)+2=-8

The solution of the system is the point (-2,-8)

The system has only one solution, because the intersection point both lines is only one point

therefore

The point (2,12) is not a solution of the system

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An employment agency specializing in temporary construction help pays heavy equipment operators $131 per day and general laborer
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Write the sum using summation notation, assuming the suggested pattern continues. 5 - 15 + 45 - 135 + ...
nalin [4]

Answer:

<em>summation of five times negative three to the power of n from n equals zero to infinity</em>

Step-by-step explanation:

<u>Summation Notation </u>

It represents the sum of a finite or infinite number of terms. Let's analyze the terms of the given succession:

5-15+45-135+...

If we take 5 as a common factor, we have

5(1-3+9-27+...)

The parentheses contain the alternate sum/subtraction of powers of 3. The odd terms are positive, the even terms are negative, thus the exponent must be n starting from 0 or n-1 starting from 1

The summation is then represented by

\sum_{n=0}^{\infty}5(-3)^n

This corresponds with the option:

<u>summation of five times negative three to the power of n from n equals zero to infinity</u>

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