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TiliK225 [7]
3 years ago
11

Poopoopeepee or peepeepoopoo

SAT
2 answers:
Sedaia [141]3 years ago
8 0

Answer:

ANY would work KWHKJAHDKJAH

MAY I HAVE BRAINLIEST :P

Explanation:

Goshia [24]3 years ago
6 0
Answer: peepeepoopoo

Step by step explanation: peepeepoopoo
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suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a
saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

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