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Murrr4er [49]
3 years ago
12

Opal plots point D at (Negative 3 and one-half, one-half). Which graph shows the location of point D?

Mathematics
2 answers:
Doss [256]3 years ago
6 0

Answer:

b

Step-by-step explanation:

IM DORA

tekilochka [14]3 years ago
6 0

Answer:

B      

\

ur welcome ......

Step-by-step explanation:

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Help plz i don’t know the answers
mixer [17]

Answer:

joe mama ;)

Step-by-step explanation:

j o e m a m a ; )

5 0
2 years ago
The coordinates of the vertices of​ quadrilateral ABCD ​ are A(−4, −1) , B(−1, 2) , C(5, 1) , and D(1, −3) .
finlep [7]

Hi there, KawallPotato! :)

Finding the slope of a line is finding the rise over run, or the change in y over the change in x. Let me show you what I mean.

Slope = change in y / change in x

Or in other words, \frac{y2 - y1}{x2 - x1}

Let's try it with AB. The first thing to consider is the placement of the letters. The blank space is asking for the slope of point A to point B, which means that the coordinates of A are your y₁ and x₁ values and the coordinates of B are your y₂ and x₂ values.

Put them in the equation like this:

\frac{2 - (-1)}{-1 - (-4)}

2 - (-1) is a double negative, so it becomes 2 + 1, which is 3.

-1 - (-4) turns into -1 + 4 for the same reason. The change in x is also 3.

\frac{3}{3} = 1, so the slope of line AB is 1.


Using the same method, we can solve the next three problems.

Coordinates of B: (-1, 2)

Coordinates of C: (5, 1)

Slope: \frac{1 - 2}{5 - (-1)} = \frac{-1}{5+1} = -\frac{1}{6}

The slope of BC is -1/6.


Coordinates of C: (5, 1)

Coordinates of D: (1, -3)

Slope: \frac{1 - (-3)}{5 - 1} = \frac{1 + 3}{5 -1} = \frac{4}{4}, so the slope is 1.


Coordinates of A: (-4, -1)

Coordinates of D: (1, -3)

Slope: \frac{-1 - (-3)}{1 - (-4)} =  -\frac{2}{5}

The slope is -\frac{2}{5}.


Quadrilateral ABCD is not a parallelogram because it has only one pair of parallel opposite sides.

I hope this was helpful. Have a great day. :D

5 0
3 years ago
Refer to the Exhibit Student Grades. The professor has informed the class that 7.93 percent of her students received grades of A
Marta_Voda [28]

This question is incomplete, the complete question is;

Refer to the Exhibit Student Grades. A professor at a local university noted that the grades of her students were normally distributed with a mean of 73 and a standard deviation of 11.

The professor has informed the class that 7.93 percent of her students received grades of A. What is the minimum score needed to receive a grade of A

Answer:

the minimum score needed to receive a grade of A is 88.51

Step-by-step explanation:

Given the data in the question;

Let x represent the grades of the students that were normally distributed with mean μ = 73 and standard deviation σ = 11.

so, The professor has informed the class that 7.93 percent of her students received grades of A

the minimum score needed to receive a grade of A will be:

P( X > x ) = 7.93 %

P( X > x ) = 0.0793

1  - P( X ≤ x ) = 0.0793

- P( X ≤ x ) = 0.0793 - 1

- P( X ≤ x ) = - 0.9207

P( X ≤ x ) = 0.9207

⇒ P( X-μ/σ ≤ x-μ/σ ) = 0.9207

so, x-μ/σ = InvNormal( 0.9207 )  

x-μ/σ = 1.41

(x - 73) / 11 = 1.41

(x - 73) = 1.41 × 11

(x - 73)  = 15.51

x = 15.51 + 73

x = 88.51

Therefore, the minimum score needed to receive a grade of A is 88.51

7 0
2 years ago
Mike,Marco,Amy,Valeria,Jeslyn,Karina,Melanie,Maria,Sonia,Edgar,Emmanuel,Joey,Anthony,Perla,David,Mia,Dominic,Isabella,Alex,Nancy
Zepler [3.9K]

Answer:

3x1_4 isnt an equation

Step-by-step explanation:

4 0
3 years ago
Write 0.007 as a fraction.<br> Do not try to simplify your answer.<br> 05<br> 금<br> Х<br> 5<br> ?
balu736 [363]

Answer:

7/1000

Step-by-step explanation:

6 0
2 years ago
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