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3 years ago

Opal plots point D at (Negative 3 and one-half, one-half). Which graph shows the location of point D?

Mathematics

2 answers:

Doss [256]3 years ago

6 0

Answer:

Step-by-step explanation:

IM DORA

tekilochka [14]3 years ago

6 0

Answer:

ur welcome ......

Step-by-step explanation:

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Solve the system of equations 9x - 4y = -7 7x - 12y = 39 x? y?

Marizza181 [45]

Answer:

x = -3

y = -5

(-3, -5)

Step-by-step explanation:

We can solve this system of equations by elimination. This is when you either add OR subtract the equations (depending on the situation) to eliminate one variable, allowing you to solve for the other. To do this, we need one variable with the same coefficient in BOTH equations.

9x - 4y = -7 X3=> 27x - 12y = -21 (New equation is still equivalent)

7x - 12y = 39

Both equations have negative "12y" in them. If you subtract - 12y from - 12y, you get 0, eliminating the variable. Subtract the two equations.

. 27x - 12y = -21 Subtract each term in the equation.

- 7x - 12y = 39 Keep equal signs aligned

. 20x - 0 = -60 'y' eliminated. -12y - (-12y) = 0

. 20x = -60 Isolate 'x'

. 20x/20 = -60/20 Divide both sides by 20

. x = -3 Solved for 'x'

Substitute 'x' for -3 in any equation.

9x - 4y = -7

9(-3) - 4y = -7 Substitute. Simplify multiplication.

-27 - 4y = -7 Isolate 'y' now

-27 + 27 - 4y = -7 + 27 Add 27 on both sides

-4y = 20 Left side cancelled out 27, right side simplified by adding.

-4y/-4 = 20/-4 Divide both sides by -4

y = -5 Solved for 'y'

Therefore the solution is when 'x' is -3 (x = -3) and when 'y' = -5 (y = -5).

You can also write the solution as an ordered pair, like coordinates, which are written (x, y). The solution would be (-3, -5).

5 0

3 years ago

Using a matrix, you can represent adding or subtracting equations by adding

Olenka [21]

Using a matrix, you CAN represent adding or subtracting equations by adding or subtracting rows of numbers. Therefore the answer is True

5 0

4 years ago

Read 2 more answers

If p is the smallest of four integers, what is their sum interms of P

xxMikexx [17]

Answer:

If p is the smallest of n consecutive integers of the same sign than we have p , p+1 , p+2 , … , p+(n−1) ,

So the sum is

∑k=0n−1(p+k)=∑k=0n−1p+∑k=0n−1k=np+n2−n2

Here n=4

So we have 4p+6

And checking

p+(p+1)+(p+2)+(p+3)=4p+6

Note if p=−v

Than you have the same thing as if p=v−n+1 just negative for example 3 consecutive integers the smallest is −5 so the sum is −5+(−4)+(−3)=3×−5+32−32=−15+3=−12

On the other hand:

−(3+4+5)=−(3×3+32−32)=−(9+3)=−12

If p=−v the sum of next v+1 integers is −(∑k=0vk)=−(v2+v2)

Than needs an other v integers to bring it up to 0 again. From there it is

∑k=0hk=h2+h2

Where h=n−(2v+1) .

So recap if p is the smallest of n consecutive integers their sum is

p+(p+1)+(p+2)+…+(p+(n−1))=⎧⎩⎨⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪⎪np+n2+n2−(n|p|+n2+n2)((n−|p|)2+(n−|p|)2)−(|p|p+|p|2+|p|2)((n−|p|)2+(n−|p|)2)n≥0p<0∧n<|p|+1p<0∧|p|<n<2|p|+1p<0∧n>2|p|+1

Step-by-step explanation:

6 0

3 years ago

Because of a problem in the program, the timer in a video player did not begin counting until the video had been playing for sev

Bess [88]

Answer:

105 frames

Step-by-step explanation:

Given that 25 frames are played per second

25 frames= 1 sec

The video already played 3 and 2/5 seconds before the player started to count 0

Write 3 and 2/5 seconds as an improper fraction

=(5*3)+2 / 5 = 17/5 seconds

Multiply by 25 frames

17/5 *25 =85 frames

So according to the video counter,after 17/5 seconds,it should count 85 frames.However,at 0 seconds,it indicated a count of 190 frames.Thus,to get the number of frames that were already in count you subtract 85 frames from the 190 frames.

190-85=105 frames.

Step-by-step explanation:

3 0

3 years ago

shakira invests $500000 at 5% compound intwerest per annum . calculate how many years it takes for the value to double in value?

Kay [80]

Answer:

$t=14.2\ years$