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chubhunter [2.5K]
3 years ago
15

What is the taxi distance from point C(2,4) to point D(1,7)

Mathematics
1 answer:
Delicious77 [7]3 years ago
5 0
I cant see my forehead
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Anna11 [10]
Check out tiger algebra you can get an answer there good luck
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3 years ago
Which of the following equations have a solution of y = -22 ? Select all that apply.
nevsk [136]

Answer:

Where are the equations?

7 0
3 years ago
A scale drawing of a square has a side length of 6 millimeters. The drawing has a scale of 1 mm : 7 km. Find the actual perimete
zvonat [6]

Answer:

The real perimeter is:

P= 24 mm *\frac{7 km}{1mm}= 168 km

And the area would be:

P = 36mm^2 *\frac{(7km)^2}{(1mm)^2} = 1764 km^2

Step-by-step explanation:

For this case we know one side of a square given 6mm.

We can begin calculating the perimeter for the scale figure with this formula:

P = 4x = 4*6 mm =24 mm

The area for this case is given by:

A = x^2 = 6mm^2 = 36 mm^2

And we know that the drawing has a scale of 1 mm : 7 km and if we convert the perimeter to km we got:

P= 24 mm *\frac{7 km}{1mm}= 168 km

And the area would be:

P = 36mm^2 *\frac{(7km)^2}{(1mm)^2} = 1764 km^2

6 0
2 years ago
Someone can help???
frozen [14]

Answer:

The slant of the ladder is 5 ft

Step-by-step explanation:

Look at the attached figure to understand this situation

∵ a represents the distance from the edge to the top step

∵ The distance from the edge to the top step is 4 ft

∴ a = 4 ft

∵ b represents the distance to the house's edge from the bottom step

∵ The distance to the house's edge from the bottom step is 3 ft

∴ b = 3 ft

∵ c represents the slant of the ladder

∴ We need to find c

→ By using the Pythagoras Theorem

∵ c = \sqrt{a^{2}+b^{2}}

∴ c = \sqrt{(4)^{2}+(3)^{2}}=\sqrt{16+9}=\sqrt{25}

∵ \sqrt{25} = 5

∴ c = 5 ft

∴ The slant of the ladder is 5 ft

5 0
3 years ago
Based on the areas of the squares determine whether the triangle shown is a right triangle
Stella [2.4K]

Answer:

The answer is "triangle ABC is not a right triangle".

Step-by-step explanation:

For a right-angle triangle:

Its square upon on longest or triangular edges is equivalent to the total of the other two squares

Its parameters indicated throughout the question are;

Square of lateral length A = 7 \ inch^2

The square of lateral length B = 18 \ inch^2

The square of lateral length C=27\  inch^2

Thus, the longest side is C, as well as the size inch^2 of the squares of its two sides, is7 + 18 = 25 \ inch^2, lower than square C = 27\ inch^2, hence, the ABC triangle is not correct. Its longest edge is consequently C.

5 0
2 years ago
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