Joe runs 9.25 times around a track in 1, 125.803 seconds. If one lap around the track is 502.3 meters,
1 answer:
Step-by-step explanation:
Speed = Distance÷Time
so
502.3÷125.803= 3.99275057
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Answer:
A and D
Step-by-step explanation:
Step-by-step explanation:
TS = 4x - 7
x = -7/4
SV = 5x -15
x = -15/5
= -3
TV = -7/4 + -3
= -3 3/4
= -4.75
Answer:
9,600/75,000, 16/125
Step-by-step explanation:
art+science=75000
<u>9600 </u>
75000 =16/125
Answer:
Using y = mx + c
slope = -17+5/3-1 = -12/2 = -6
Using point (1 , - 5)
y + 5 = -6(x - 1)
y + 5 = - 6x + 6
y = - 6x + 6 - 5
y = - 6x + 1
Hope this helps.
