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3 years ago

AYUDAAAAAAAAAAAAAAAAAAAAAAAAAAAAA PLIS

Mathematics

1 answer:

lorasvet [3.4K]3 years ago

7 0

Answer:

es difícil verdad amigo

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1<br> The measure of Z1 =

ollegr [7]

Answer:

∠1 = 90°

Step-by-step explanation:

The angle inscribed in a semicircle is always 90°

∠1 = 90°

3 0

3 years ago

George traveled 300 miles in 8 hours. How far could he travel in 4 hours if he traveled at the same rate?

Amiraneli [1.4K]

Divide 300 by 8 to find the unit rate
300/8= 37.5

He travels 37.5 miles per hour

If he travels 37.5 miles per hour, to find the amount in 4 hours we would do 37.5 times 4

37.5×4=150

In 4 hours he travels 150 miles

8 0

3 years ago

Read 2 more answers

Mrs. Rodriguez is going to use 6 1 3 material to make two dresses. The larger dress requires 3 2 3 yards of material. How much m

MArishka [77]

So she need to use 500

5 0

3 years ago

A company studied the number of lost-time accidents occurring at its Brownsville, Texas, plant. Historical records show that 6%

Georgia [21]

Answer:

$\% E = 0.9 \%$

$\%E_1 = 10.1 \%$

Step-by-step explanation:

From the question we are told that

The probability that an employees suffered lost-time accidents last year is $P(e) = 0.06$

The probability that an employees suffered lost-time accident during the current year is

$P(c) = 0.05$

The probability that an employee will suffer lost time during the current year given that the employee suffered lost time last year is

$P(c | e) = 0.15$

Generally the probability that an employee will experience lost time in both year is mathematically represented as

$P(c \ n \ e) = P(e) * P(c \ |\ e)$

=> $P(c \ n \ e) = 0.06* 0.15$

=> $P(c \ n \ e) = 0.009$

Generally the percentage of employees that will experience lost time in both year is mathematically represented as

$\% E = P(e \ n \ c ) * 100$

=> $\% E = 0.009 * 100$

=> $\% E = 0.9 \%$

Generally the probability that an employee will experience at least one lost time accident over the two-year period is mathematically represented as

$P(e \ u \ c) = P(e) + P(c) - P(e \ n \ c)$

=> $P(e \ u \ c) = 0.06 + 0.05 - 0.009$

=> $P(e \ u \ c) = 0.101$

Generally the percentage of the employees who will suffer at least one lost-time accident over the two-year period is mathematically represented as

$\%E_1 = P(e \ u \ c) * 100$

=> $\%E_1 = 0.101* 100$

=> $\%E_1 = 10.1 \%$

7 0

3 years ago

Inscribe a circle in a unit square and to r= 1000 random.

Oduvanchick [21]

Step-by-step explanation:

area of square = 1

area of a circle in square = $\pi r^2 = \pi *(1/2)^2 = \frac{\pi }{4}$

bu estimate $p^ = X/n = 760/1000 = 0.76Therefore, 
[tex]\frac{\pi }{4} \approx 0.76$

$\pi \approx 0.76*4 =3.04$

b) if n tend to infinity

$\pi will approach 3.14$

6 0

3 years ago