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Westkost [7]
3 years ago
14

Find the measure of angle 2 if the measure of angle 8 is 40 degrees.

Mathematics
2 answers:
SOVA2 [1]3 years ago
8 0

Answer:

2=40°

Step-by-step explanation:

Alla [95]3 years ago
8 0

Answer:

Below.

Step-by-step explanation:

40 degrees as < 2 and < 8 are exterior alternate angles.

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PLEASE HELP! <br><br>Identify the y-intercept and zeros of <br>y = x^4 - 9x^2 - 36<br>Algebraically​
const2013 [10]

Answer:

Our y-intercept is (0, -36).

Our real zeros are: (-2√3, 0) and (2√3, 0)

And our imaginary zeros are: (i√3, 0) and (-i√3, 0)

Step-by-step explanation:

We have the function:

y=x^4-9x^2-36

Let's identify the y- and x-intercepts.

Y-Intercept:

To determine the y-intercept, we will substitute 0 for x and solve for y. So:

y=(0)^4-9(0)^2-36

Evaluate:

y=-36

Therefore, our y-intercept is at (0, -36).

X-Intercepts:

To determine our x-intercepts, we need to substitute 0 for y and solve for x. So:

0=x^4-9x^2-36

Now, we can factor. Before doing so, we can make the factored easier to see by converting this into quadratic form. Let's let u=x². Then:

0=(u^2)^2-9(x^2)-36

Substitute:

0=u^2-9u-36

Now, let's factor. We can use -12 and 3. So:

0=u^2+3u-12u-36 \\ 0=(u(u+3)-12(u+3)) \\ 0=(u-12)(u+3)

Now, we can substitute back u:

0=(x^2-12)(x^2+3)

Zero Product Property:

x^2-12=0\text{ or } x^2+3=0

Solve for x in each case:

x^2=12 \text{ or } x^2=-3

Take the square root of both sides. Since we're taking an even root, we will need plus/minus. Therefore:

x=\pm\sqrt{12}=\pm2\sqrt{3}\text{ or } x=\pm\sqrt{-3}=\pm i\sqrt{3}

Therefore, our zeros (both real and imaginary) are: (2√3, 0), (-2√3, 0), (i√3, 0), and (-i√3, 0)

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Step-by-step explanation:

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