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DaniilM [7]
4 years ago
11

What is the equation of the line shown?

Mathematics
2 answers:
Aleksandr-060686 [28]4 years ago
7 0

Answer:

C) y=1/6x

Step-by-step explanation:

Because when x=6, y=1, when x=12, y=2. And when x=18, y=3.

tankabanditka [31]4 years ago
6 0

Answer:

y= 1/6x

Step-by-step explanation:

You might be interested in
8,502,000,000,000 <br> in scientific notation
ElenaW [278]

Answer:

are you supposed to do math

3 0
3 years ago
What's is the answer to the equation 4(x+7)=9(x-1)+22 ?
Aleks [24]
Hello, there!

What's the answer to the equation 4(x + 7) = 9(x - 1) + 22 


Answer: x = 3
------------------------------------------------------------------------------------------------------

Explanation:


First, let's simplify this
4 * x = 4x

4 * 7 = 28

Now, we have 4x + 28 = 9(x - 1) + 22

Now, let's simplify the right side by using the distributive property as well.

9 * x = 9x

9 * -1 = -9

Now, we have 4x + 28 = 9x -9 + 22

Let's combine like terms on the right side

-9 + 22 = 13

Npw, we have 4x + 28 = 9x + 13

Let's isolate the x. To do this, we will first subtract 28 from each side.

4x + 28 = 9x + 13
       -28           -28

4x = 9x - 15

Now, we will subtract 9x from each side.

4x = 9x - 15
-9x   -9x

-5x = -15

Now, we will multiply each side by -1 to make x a positive number.

-5x = -15
*-1    *-1

5x = 15

Finally, we will simplify this completely. To do this, we will divide each side by 5.

5x = 15
---    ----
 5      5

x = 3


Our final answer is x = 3


I hope I helped!

Let me know if you need anything else!

~ Zoe
7 0
4 years ago
Last month, he sold 50 chickens and 30 ducks for $550. This month, he sold 44 chickens and 36 ducks for $532
IgorC [24]
The answer is chicken $8, duck $5

x - the cost of a chicken
y - the cost of a duck

<span>he sold 50 chickens and 30 ducks for $550: 50x + 30y = 550
</span><span>he sold 44 chickens and 36 ducks for $532: 44x + 36y = 532

</span>50x + 30y = 550                divide by 10
44x + 36y = 550                 divide by 4
______________
50x/10 + 30y/10 = 550/10
44x/4 + 36y/4 = 532/4
______________
5x + 3y = 55                                    Multiply by (-3)
11x + 9y = 133
______________
5x * (-3) + 3y * (-3) = 55 * (-3)
11x + 9y = 133
______________
-15x - 9y = -165
11x + 9y = 133
______________
Sum up:
-4x + 0y = -32
-4x = -32
x = -32/-4
x = 8


Since 5x + 3y = 55  and x = 8, then:
5 * 8 + 3y = 55
40 + 3y = 55
3y = 55 - 40
3y = 15
y = 15/3
y = 5
5 0
3 years ago
Read 2 more answers
Convert to scientific notation ​
andreev551 [17]

Answer:

8.245*10^6

Step-by-step explanation:

scientific notation is known as c*10^n

c : any number from 1-10

n : the power of base 10

the number in our case between 1 and 10 is 8.245

but then we want to move the decimal 6 spaces to the right, so we multiply that by 10^6

8 0
4 years ago
Given the general identity tan X =sin X/cos X , which equation relating the acute angles, A and C, of a right ∆ABC is true?
irakobra [83]

First, note that m\angle A+m\angle C=90^{\circ}. Then

m\angle A=90^{\circ}-m\angle C \text{ and } m\angle C=90^{\circ}-m\angle A.

Consider all options:

A.

\tan A=\dfrac{\sin A}{\sin C}

By the definition,

\tan A=\dfrac{BC}{AB},\\ \\\sin A=\dfrac{BC}{AC},\\ \\\sin C=\dfrac{AB}{AC}.

Now

\dfrac{\sin A}{\sin C}=\dfrac{\dfrac{BC}{AC}}{\dfrac{AB}{AC}}=\dfrac{BC}{AB}=\tan A.

Option A is true.

B.

\cos A=\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}.

By the definition,

\cos A=\dfrac{AB}{AC},\\ \\\tan (90^{\circ}-A)=\dfrac{\sin(90^{\circ}-A)}{\cos(90^{\circ}-A)}=\dfrac{\sin C}{\cos C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AC}}=\dfrac{AB}{BC},\\ \\\sin (90^{\circ}-C)=\sin A=\dfrac{BC}{AC}.

Then

\dfrac{\tan (90^{\circ}-A)}{\sin (90^{\circ}-C)}=\dfrac{\dfrac{AB}{BC}}{\dfrac{BC}{AC}}=\dfrac{AB\cdot AC}{BC^2}\neq \dfrac{AB}{AC}.

Option B is false.

3.

\sin C = \dfrac{\cos A}{\tan C}.

By the definition,

\sin C=\dfrac{AB}{AC},\\ \\\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.

Now

\dfrac{\cos A}{\tan C}=\dfrac{\dfrac{AB}{AC}}{\dfrac{AB}{BC}}=\dfrac{BC}{AC}\neq \sin C.

Option C is false.

D.

\cos A=\tan C.

By the definition,

\cos A=\dfrac{AB}{AC},\\ \\\tan C=\dfrac{AB}{BC}.

As you can see \cos A\neq \tan C and option D is not true.

E.

\sin C = \dfrac{\cos(90^{\circ}-C)}{\tan A}.

By the definition,

\sin C=\dfrac{AB}{AC},\\ \\\cos (90^{\circ}-C)=\cos A=\dfrac{AB}{AC},\\ \\\tan A=\dfrac{BC}{AB}.

Then

\dfrac{\cos(90^{\circ}-C)}{\tan A}=\dfrac{\dfrac{AB}{AC}}{\dfrac{BC}{AB}}=\dfrac{AB^2}{AC\cdot BC}\neq \sin C.

This option is false.

8 0
3 years ago
Read 2 more answers
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