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3 years ago

At what point do the lines y = -x + 5 and y = 2x – 1 intersect?

Mathematics

1 answer:

olganol [36]3 years ago

8 0

They intersect at the point (2,3).

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Please help<br><br> -3/4(8n + 12) = 3(n-3)

Dennis_Churaev [7]

Step-by-step explanation:

$- \frac{3}{4} (8n + 12) = 3(n - 3)$

$- 3(8n + 12) = 12(n - 3)$

$\cancel{- 3}(8n + 12) = \cancel{12}(n - 3)$

$- (8n + 12) = 4(n - 3)$

$- 8n - 12 = 4n - 12$

$- 8n - 4n = - 12 + 12$

$- 12n = 0$

$n = 0$

8 0

3 years ago

Lost as usual yep I am

denpristay [2]

Answer:

y = -3x -4

Step-by-step explanation:

A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.

The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.

The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...

3(x+3) +(y-5) = 0

This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:

3x +9 +y -5 = 0 . . . . . eliminate parentheses

y = -3x -4 . . . . . subtract terms that are not "y"

8 0

3 years ago

Read 2 more answers

Sketch the region enclosed by the given curves. Decide whether to integrate with respect to x or y. Draw a typical approximating

MakcuM [25]

Answer:

A=8.4063 $u^{2}$

Step-by-step explanation:

Be the functions:

$y=\frac{3}{x};y=\frac{3}{x^{2}}:x=7$

according the graph:

$\int\limits^1_7 {\frac{3}{x} } \, dx -\int\limits^1_7 {\frac{3}{x^{2} } } \, dx =3\int\limits^1_7 {\frac{1}{x} } \, dx -3\int\limits^1_7 {\frac{1}{x^{2} } } \, dx=3(\int\limits^1_7 {\frac{1}{x} } \, dx -\int\limits^1_7 {\frac{1}{x^{2} } } \, dx)=3[lnx-\frac{1}{x}](1-7)=3[(ln7-ln1)-(\frac{1}{7}-1)]=3[(1.945-0)-(0.1428-1)]=3*(1.945+0.8571)=3*2.8021=8.4063u^{2}$