(X+5)²=4/4
X+5=1, X+5=-1
X=1-5 X=-1-5
X=-4 X=-6
B=7
3(b-4)+5b=44
3b-12+5b=44
8b=44+12
8b=56
b=7
83 would be the answer. You don’t gotta multiply or anything
For the answer to the question above asking w<span>hat is the probability of randomly choosing a gold chip, not replacing it, and then randomly choosing another gold chip? The answer to this question is the third one among the choices which is c. 1 over 30.
I hope this helped</span>
