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beks73 [17]
3 years ago
5

What is proportion as applied in mathematics​

Mathematics
1 answer:
Mariana [72]3 years ago
5 0

Answer:

Proportion is a mathematical comparison between two numbers. According to proportion, if two sets of given numbers are increasing or decreasing in the same ratio, then the ratios are said to be directly proportional to each other. Proportions are denoted using the symbol "::" or "=".

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What is the solution of the system?
gulaghasi [49]

Answer: \bold{\text{b.}\bigg(4,-\dfrac{1}{2}\bigg)}

<u>Step-by-step explanation:</u>

x - 2 = -4y  →  x = 2 - 4y

3x + 2y = 11  

3(2 - 4y) + 2y = 11     <em>replaced "x" with (2 - 4y)</em>

6  - 12y + 2y = 11     <em>distributed "3" on left side</em>

<em> </em>6   - 10y        = 11      <em>added like terms (-12y + 2y)</em>

     - 10y        =  5      <em>subtracted "6" from both sides</em>

          y         = -\dfrac{1}{2}       <em>divided both sides by -10</em>


Next, solve for x:

x = 2 - 4y

   = 2 - 4(-\frac{1}{2} )

   = 2 + 2

   = 4

7 0
3 years ago
Explain how you would find the slope of the line y = 4.
Slav-nsk [51]

Answer:

The slope is 0.

Step-by-step explanation:

You could draw it on graphs paper . It will be a horizontal line passing through the point (0,4). y will always be 4 and x can be any value.

The slope of a horizontal line is 0.

4 0
3 years ago
Can someone help me simplify these expressions
Gnesinka [82]

Answer:

-6v^7

p^6

Step-by-step explanation:

-1v^3 \times -2v^2 \times -3v^2

-6v^{3+2+2}

-6v^7

1/2p^2 \times p^3 \times 2p

1/2p^2 \times 1p^3 \times 2p

1p^{2+3+1}

1p^6

8 0
3 years ago
jone is on a diet that allows him to eat 2000 calories per day he wants to eat a peice of cake that 700 calories what percent of
Mandarinka [93]
The answer is 35% because I did 700 is ____% of 2000 and when I solved the equation, my answer was 35%
Hope this helped!!
~melany~
6 0
3 years ago
Read 2 more answers
@ny help please please
Ulleksa [173]
The expected value for the game would be the first one negative three
6 0
3 years ago
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