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bekas [8.4K]
2 years ago
15

A student takes an 18-question, multiple-choice exam with five choices for each question and guesses on each question. Assume th

e variable is binomial. Part: 0 / 20 of 2 Parts Complete Part 1 of 2 Find the probability of guessing at least 9 out of 18 correctly. Round the answer to at least four decimal places.
Mathematics
1 answer:
Kobotan [32]2 years ago
7 0

Answer:

Probability of getting at least 9 out of 18 correctly is 0.0043

Step-by-step explanation:

We have

n = 18

p = 1/5 for correct answer

q = 4/5 for wrong answer

P( 9 \leq X \leq 18) = 1 - P(0 \leq X\leq 8)

                       = 1 -  0.9957

                         =0.0043

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Rufina [12.5K]

Answer:

c = 1190.2

Step-by-step explanation:

We have the following solution:

y(x) = ce^{-2x} + e^{-x}

We want to find the value of x that satisfies the following condition:

y(3) = 3.

This means that when x = 3, y = 3. So

y(x) = ce^{-2x} + e^{-x}

y(3) = ce^{-2*3} + e^{-3}

3 = ce^{-6} + e^{-3}

3 = ce^{-6} + 0.0498

ce^{-6} = 2.9502

c = \frac{2.9502}{e^{-6}}

c = 1190.2

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2 years ago
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Answer:

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