All categories

3 years ago

What is the equation in slope-intercept form of the line that has a slope of -2/3, and passes through the point (6, 2)?

Mathematics

1 answer:

Jet001 [13]3 years ago

3 0

Answer:

Y=-2/3x+6

Step-by-step explanation:

Y=-2/3x+b

2=-2/3•6+b

2=-4+b

6=b

You might be interested in

Please explain how to get answer in sq units of parallelogram ABCD

Lostsunrise [7]

Hey there :)

Assuming you are asking how to find the area of parallelogram ABCD:

We know the area formula of a parallelogram:
Area = base x height

Then apply the formula to the given.

7 0

3 years ago

What is incorrect in this? And how do I correct it?

german

$\bf \begin{cases} y=3x+2\\ -3x+y=2\\ 3x-y=-2\\ ------\\ 6x-2y=10 \end{cases}\implies \begin{cases} 3x-y=-2\\ 6x-2y=10 \end{cases}\implies \begin{bmatrix} 3&-1&|&-2\\ 6&-2&|&10 \end{bmatrix}\\\\ -------------------------------$

$\bf \stackrel{\textit{system's determinant}}{ \begin{bmatrix} 3&-1\\6&-2 \end{bmatrix}\implies (3\cdot -2)-(6\cdot -1)}\implies -6-(-6)\implies -6+6\implies 0 \\\\\\ \stackrel{\textit{systerm determinant of 0 means}}{\textit{the system has \underline{no solutions } or \underline{infinitely many solutions}}}$

7 0

3 years ago

Could i please get some help to Evaluate -a- (−8)+b where a =2 and b = -7

Igoryamba

Answer: -1

Explanation:
-a - (-8) + b
-a + 8 + b (because the - - signs cancel out)
-(2) + 8 + (-7)
-2 + 8 - 7 = -1

3 0

4 years ago

Read 2 more answers

What is the domain of the relation?<br>{(-3, - 4), (-1, 2), (0, 0), (1, 3), (5, 4)]

mezya [45]

The domain are the X values.

Each set of parenthesis is written as (x,y), so the domain would be the first number in each set of parenthesis.

{-3, -1, 0, 1, 5}

6 0

3 years ago

Each year the US Environmental Protection Agency (EPA) releases fuel economy data on cars manufactured in that year. Below arc s

fomenos

Answer:

Follows are the solution to this question:

Step-by-step explanation:

Please find the complete question in the attachment file.

$n_1 = 26 \\\\ x_1 = 16.12 \\\\s_1 = 3.58\\\\n_2 = 26\\\\ x_2 = 19.85 \\\\ s_2 = 4.51$

$H_0: u_1 = u_2\\\\H_1: u_1 \neq u_2$

Using formula:

$\to S^{2}_{p}=\frac{S^{2}_{1}(n_1 -1)+ S^{2}_{2}(n_2-1)}{n_1+n_2-2}$

$\to Sp^2 = \frac{((26-1) \times (3.58^2) + (26-1) \times (4.51^2))}{(26+26-2)}$

$= \frac{((25) \times 12.8164 + (25) \times 20.3401 )}{(26+24)}\\\\ = \frac{(320.41 + 508.5025)}{(50)}\\\\ = \frac{(828.9125)}{(50)}\\\\=16.57825$

$\to Sp = 4.0716$

Calculating the value of standard error:

$\to SE = Sp \times \sqrt{\frac{1}{n_1}+\frac{1}{n_2}}$

$=4.0716 \times \sqrt{\frac{1}{26}+\frac{1}{26}}\\\\=4.0716 \times \sqrt{\frac{1+1}{26}}\\\\=4.0716 \times \sqrt{\frac{2}{26}}\\\\=4.0716 \times \sqrt{\frac{1}{13}}\\\\=4.0716 \times 0.277 \\\\=1.1278332\\\\= 1.1293$