-3(6-10v-5v)
=-3(6-15v)
=-18+45v
-18+45v is the final answer.
The price of the shoes times .06 will give you the abswer
The definite integral from x=2 to x=k of (6x-5) is
x^2
6*------- - 5x, [2,k] or 3[ k^2 -5k] - 3 [ 2^2 - 5(2) ]
2 or
3[k^2 - 5k] - 3[4-10] = 10 (as given)
3k^2 -15k + 18 = 10, or
3k^2 - 15k + 8 = 0
This is a quadratic equation; solve it using the quadratic formula:
-(-15) plus or minus sqrt( [-15]^2 - 4(3)(8) )
k = ------------------------------------------------------------
6
15 plus or minus 26.36
= ------------------------------------
6
Answer:
the following 3 equations are equivalent :
• x + 1 = 4
• 2 + x = 5
• -5 + x = -2
Step-by-step explanation:
2 + x = 5
x + 1 = 4
9 + x = 6
x + (- 4) = 7
-5 + x = - 2
Let’s take this equation :
x + 1 = 4
=======
By Adding 1 to both sides of the equation we get :
x + 1 + 1 = 4 + 1
⇔ x + 2 = 5
⇔ 2 + x = 5
Then the equations x + 1 = 4 and 2 + x = 5 are equivalent.
…………………………………………………………………
On the other hand ,if we subtract 6 from both sides
of the equation x + 1 = 4 we get :
x + 1 - 6 = 4 - 6
⇔ x - 5 = -2
⇔ -5 + x = -2
Then the equations x + 1 = 4 and -5 + x = -2 are equivalent.
