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kramer
3 years ago
9

Described and correct the error and finding slope and the y intercept of the graph of a linear equation.

Mathematics
1 answer:
Ludmilka [50]3 years ago
3 0

Compare y = 4x -  3 to the standard

                y = mx + b.

You can see immediately that the slope, m, is 4 and that the y-intercept, b, is -3.  The error lay in the explanation (see the problem statement) that the y-intercept is 3.  That's not correct.

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omeli [17]

Answer:

10

Step-by-step explanation:

5 0
3 years ago
Area
pentagon [3]

Step-by-step explanation:

1. In PQN & SRT.

a. <RST=<QPN (corresponding angle PQllSR)

b. <STR = <PNQ (corresponding angle TRIINQ)

c. TR=QN (Since TN & QN are opp. Side of parallelogram QNTR)

d. .°.PQN~=SRT.

2.PQN=PSOQ+SNO (whole part axiom)

3.SRT = SNO + NTRO(same as above)

4. PQN=SRT (From st. 1d)

or, PS0Q+SNO =SNO + NTRO (Cancellation of SNO)

or, PS0Q=NTRO

or, PSOQ +QOR=NTRO +QOR (Adding QOR on both side)

or, .°.◼️PQRS = ◼️QRTN

Best of luck!!!!.

8 0
4 years ago
5 + (-2)=<br> A. -3<br> B. 3<br> C. -2<br> D. -5<br> E. 0
JulsSmile [24]

Answer:

it is b because I did the math and got that

5 0
4 years ago
Read 2 more answers
Mr. Bond’s class wanted to estimate the mean mass of Snickers Fun Size bars. They randomly selected 74 bars and recorded the mas
AleksAgata [21]

Step 1: Find the standard error (SE)

The standard error is given by

SE=\frac{s}{\sqrt[]{n}}\begin{gathered} \text{ Where } \\ SE=\text{ the standard error} \\ s=\text{ the sample standard deviation} \\ n=\text{ the sample size} \end{gathered}

In this case,

n=74,s=0.76

Therefore,

SE=\frac{0.76}{\sqrt[]{74}}\approx0.0883

Step 2: Find the alpha level (α)

\alpha=1-\frac{(\text{Confidence level})}{100}\alpha=1-0.99=0.01

Step 3: Find the critical probability (P*)

P^{\prime}=1-\frac{\alpha}{2}

Therefore,

P^{\cdot}=1-\frac{0.01}{2}=0.995

Step 4: Find the critical value (CV)

The critical value the z-score having a cumulative probability equal to the critical probability (P*).

Using the cumulative z-score table we will find the z-score with value of 0.995

Hence,

CV=2.576

Step 5: Find the margin of error (ME)

ME=SE\times CV

Therefore,

ME=0.0883\times2.576=0.2275

Step 6: Find the confidence interval (CI)

\begin{gathered} CI\text{ is given by} \\ CI=(\bar{x}-ME,\bar{x}+ME) \\ \text{ In this case} \\ \bar{x}=17.1 \end{gathered}

Therefore,

CI=(17.1-0.2275,17.1+0.2275)=(16.8725,17.3275)

Hence there is a 99% probability that the true mean will lie in the confidence interval

(16.8725, 17.3275)

4 0
1 year ago
Ivan biked 1 whole 2/3 on Monday, 2 wholes 1/3 hours on Tuesday, and 2 wholes 2/3 on Wednesday. What is the total number of hour
GenaCL600 [577]
1 \frac{2}{3} + 2 \frac{1}{3} + 2 \frac{2}{3} =

\frac{3*1+2}{3} +  \frac{3*2+1}{3} +  \frac{3*2+2}{3} =

\frac{3+2}{3} +  \frac{6+1}{3} +  \frac{6+2}{3} =

\frac{5}{3} + \frac{7}{3} + \frac{8}{3} =

=  \frac{20}{3} h

In hours:

20 |_3
(2)....6hs
x60' 
------
120' |_3
(0)....40' 

Answer:
<span>6hs40min

</span>or<span>

</span>\frac{20}{3} hs =  \frac{20}{3} *60' =  \frac{1200}{3} = 400'
<span>
400' = 6*60' = 360' + 40' = 400' (True)
</span>Until

<span>6hs40min</span>
5 0
3 years ago
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