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kap26 [50]
3 years ago
9

Brent would like to start a small landscape business this summer. He has a lawn mower, but needs a truck to carry the lawn mower

and other supplies. He has saved $5,700.
Since his uncle knows a lot about trucks, he decides to ask him for some help. His uncle recommends a few truck models and suggests that he pay attention to how many miles the car has. His uncle reminds him that he will need to pay for the sales tax and license for the car. Brent sets aside $800 for these expenses. He does some research and finds the following trucks within his budget:

1996 Ford F150 2000 Toyota Tundra 1998 Chevrolet 1500
red white red
8 cylinder 6 cylinder 6 cylinder
automatic manual automatic
124,365 miles 106,675 miles 120,325 miles
$4,495 $4,899 $4,795
Brent thinks about how much he will need to pay for car insurance. He thinks that it would be a good idea to get quotes on auto insurance for the models that he is considering. He also thinks about the truck's gas mileage and how the truck was rated.

Use the PACED decision-making process to make the decision for Brent. Show your work.
Mathematics
1 answer:
spin [16.1K]3 years ago
3 0

Answer:

I would buy the 2000 Toyota Tundra. Yes it is the most expensive, but it is the newest so it should require less expense money for problems, it is a manual transmission 6 cylinder so it should get better gas mileage, and it has fewer miles. The rankings of these trucks are not provided, however a Toyota tundra is considered to be a workhorse in the truck. If this is an opinion question, that's my choice.

Step-by-step explanation:

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A researcher claims that the mean of the salaries of elementary school teachers is greater than the mean of the salaries of seco
Brut [27]

Answer:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

Step-by-step explanation:

Data given and notation

\bar X_{A}=48250 represent the mean of elementary teachers

\bar X_{B}=45630 represent the mean for secondary teachers

s_{A}=3900 represent the sample standard deviation for elementary teacher

s_{B}=5530 represent the sample standard deviation for secondary teachers

n_{A}=26 sample size selected

n_{B}=24 sample size selected  

\alpha=0.05 represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

p_v represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean of the salaries of elementary school teachers is greater than the mean of the salaries of secondary school teachers, the system of hypothesis would be:

Null hypothesis:\mu_{A}-\mu_{B}\leq 0

Alternative hypothesis:\mu_{A}-\mu_{B}>0

We don't know the population deviations, so for this case is better apply a t test to compare means, and the statistic is given by:

t=\frac{(\bar X_{A}-\bar X_{B})}{\sqrt{\frac{s^2_{A}}{n_{A}}+\frac{s^2_{B}}{n_{B}}}} (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other".

Calculate the statistic

We can replace in formula (1) the info given like this:

t=\frac{(48250-45630)}{\sqrt{\frac{3900^2}{26}+\frac{5530^2}{24}}}}=1.921  

P-value

The first step is calculate the degrees of freedom, on this case:

df=n_{A}+n_{B}-2=26+24-2=48

Since is a one sided test the p value would be:

p_v =P(t_{(48)}>1.921)=0.0303

Conclusion

If we compare the p value and the significance level given \alpha=0.05 we see that p_v so we can conclude that we have enough evidence to reject the null hypothesis, and we can conclude that the mean for elementary school teachers is significantly higher than the mean for secondary teachers at 5% of significance

5 0
3 years ago
Please help for brainliest.
Kaylis [27]

Answer:

its C

Step-by-step explanation:

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A fair die is rolled 5 times. what is the probability of having no 2 and no 5 among the rolls ?
morpeh [17]
Try 4 because a die has six sides and 6-2=4
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Kierra recorded her daily exercise activity for a month in this frequency table. Which problem shows how to solve for the follow
sineoko [7]

Answer:

i accidentaly put awnser and i dont know how to get out of here

Step-by-step explanation:

6 0
3 years ago
An indoor running track is 200 meters in length. During a 3,000-meter race, runners must complete 15 laps of the track. An elect
Vlad1618 [11]

The true statement based on the histogram is

There were no lap times between 35 and 36 seconds.

The correct option is (A).

<h3>What is Histogram?</h3>

A histogram is a graphical representation that organizes a group of data points into user-specified ranges.

Given:

indoor running track is 200 meters in length.

Also, a 3,000-meter race, runners must complete 15 laps of the track.

As, there no data for interval 35-36.

So, there were no lap times between 35 and 36 seconds.

Hence, The interval from 37 to 38 seconds saw the most lap times.

Learn more about histogram here:

brainly.com/question/16819077

#SPJ1

8 0
2 years ago
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