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andrew-mc [135]
3 years ago
10

Complete the table using the Linear model: y = 2x + 1

Mathematics
1 answer:
Viefleur [7K]3 years ago
8 0
Tried my best to plot it:)

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(8, -3), m = 2<br> point slope form equation
pentagon [3]

Answer:

y=2x+14

Step-by-step explanation:

y=mx+b

hope its right

4 0
3 years ago
Read 2 more answers
Which of the following represents the solution to 3x^2+35=7x^2-4x<br> need help ASAP
mina [271]

Answer:

F

Step-by-step explanation:

4x^2 - 4x - 35 = 0

factor

(2x + 5)(2x - 7) = 0

x = -5/2, x = 7/2

that's F

4 0
3 years ago
three bags of sweets weigh 27/4 kg. two of them have the same weight and the third bag is heavier than each of the bags of equal
Nana76 [90]

I'm here buddy,

so, let's take the value of the two bags with equal weight as x.

=     x + x + (x + \frac{6}{5}) = \frac{27}{4}

=     3x + \frac{6}{5} = \frac{27}{4}

=     3x = \frac{27}{4} - \frac{6}{5}

( let's take the LCM of 4 and 5 = 20

=     3x = \frac{135}{20} - \frac{24}{20}

=     3x = \frac{111}{20}

=       x = \frac{111}{20} ÷ \frac{3}{1} = \frac{111}{20} × \frac{1}{3} = \frac{37}{20}

So, the weight of the equal bags are \frac{37}{20} and the weight of the third bag ( heavy one ) is \frac{37}{20} + \frac{6}{5} = \frac{37}{20} + \frac{24}{20} = \frac{61}{20}

1st bag =     \frac{37}{20} kg

2nd bag =  \frac{37}{20} kg

3rd bag =   \frac{61}{20} kg

Hope it helps...

7 0
3 years ago
F(x) = x2+3x+2 x2+5x+4 Why is there no zero at x = –1?
dmitriy555 [2]
You could rewrite F(x) as

\dfrac{x^2+3x+2}{x^2+5x+4}=\dfrac{(x+1)(x+2)}{(x+1)(x+4)}

and be tempted to cancel out the factors of x+1. But this cancellation is only valid when x\neq-1.

When x=-1, you end up with the indeterminate form \dfrac00, which is why -1 is not a zero.
7 0
4 years ago
NEED HELP! ASAP! 50 POINTS!
Lerok [7]

Answer:

y=13\text{ miles per gallon}

Step-by-step explanation:

We have the two points: (0, 11) and (3, 50).

And we want to find the rate of change in y relative to x, where x is the gallons and y is the miles.

In simple terms, we want to find the slope between the two points.

So, let's use the slope formula:

m=\frac{y_2-y_1}{x_2-x_1}

Let (0, 11) be (x₁, y₁) and let (3, 50) be (x₂, y₂). Substitute. Let's also put "miles" in the numerator with the Ys and "gallons" in the denominator with the Xs. This yields:

y=\frac{50-11\text{ miles}}{3-0\text{ gallons}}

Subtract and reduce:

y=39\text{ miles}/3\text{ gallons}=13\text{ miles per gallon}

And we're done!

6 0
3 years ago
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