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Andreas93 [3]
3 years ago
12

In 1910, halley's comet traveled close to earth about 1/7 of the distance from the earth to the sun. Earth's distance from the s

un is 149.6 million kilometers. ( if u answer all them i'll give u brainliest but if not its alr)
1. How close was halley's comet to earth in 1910?create an equation to answer the question.

2. estimate the next 3 years when halley's comet will appear.

3. the core of halley's comet is oblong in shape, with its longest dimension 16 km long. earth's diameter is about 12,700 km . how many times larger in diameter is earth than halley's comet?
Mathematics
1 answer:
otez555 [7]3 years ago
6 0

Answer:

Imma answer this because I don’t want this to get deleted for not bein answered and there free point who wouldn’t want them, lol :)

Step-by-step explanation:

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Line JM intersects line GK at point N. Which statements are true about the figure? Check all that apply.
ki77a [65]
See attached image

First, we must know this: Complementary angles are two angles whose sum is equal to 90°, while supplementary angles are two angles whose sum is equal to 180°. That been said, the only statement which is true is the second statement, <span>MNL is complementary to KNL

Reasons why others are False
</span>GNJ is supplementary to JNK, not complementary
MNG is supplementary to GNJ, not complementary
LNJ (not KNJ) <span>is supplementary to MNL
</span>GNM is equal to JNK, not supplementary

8 0
3 years ago
Read 2 more answers
Line segment PQ, with endpoints graphed on a coordinate grid at P(2,-2) and Q(5,-2) is translated four units to the left and two
Oxana [17]

Answer: 3

Step-by-step explanation:

We know that since a translation is a rigid motion, and that rigid motions preserve distance, the length of the transformed segment is the same as the given line segment.

5 0
2 years ago
CAN YOU HELP ME ND WHO LOVE BILLIE ELISHIE
Alla [95]
I don’t like billies music but i like her as a person
8 0
3 years ago
Read 2 more answers
A certain bridge arch is in the shape of half an ellipse 106 feet wide and 33.9 feet high. At what horizontal distance from the
nata0808 [166]

Answer:

The horizontal distance from the center is 49.3883 feet

Step-by-step explanation:

The equation of an ellipse is equal to:

\frac{x^2}{a^{2} } +\frac{y^2}{b^{2} } =1

Where a is the half of the wide, b is the high of the ellipse, x is the horizontal distance from the center and y is the height of the ellipse at that distance.

Then, replacing a by 106/2 and b by 33.9, we get:

\frac{x^2}{53^{2} } +\frac{y^2}{33.9^{2} } =1\\\frac{x^2}{2809} +\frac{y^2}{1149.21} =1

Therefore, the horizontal distances from the center of the arch where the height is equal to 12.3 feet is calculated replacing y by 12.3 and solving for x as:

\frac{x^2}{2809} +\frac{y^2}{1149.21} =1\\\frac{x^2}{2809} +\frac{12.3^2}{1149.21} =1\\\\\frac{x^2}{2809}=1-\frac{12.3^2}{1149.21}\\\\x^{2} =2809(0.8684)\\x=\sqrt{2809(0.8684)}\\x=49.3883

So, the horizontal distance from the center is 49.3883 feet

8 0
3 years ago
At a basketball game, a vender sold a combined total of 223 sodas and hot dogs. The number of hot dogs sold was 57 less than the
AnnZ [28]

Answer: 140 Hot dogs and 83 sodas.


Step-by-step explanation:

Alright, so we will say that h = hot dogs and s = sodas.

h + s = 223

I have used the guess and test strategy to get:

h = 140

140 - 57 = 83

s = 83

Check: 83 + 140 = 223

4 0
3 years ago
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