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Paul [167]
2 years ago
6

Find the area of the kite please. image included!!!

Mathematics
1 answer:
guapka [62]2 years ago
6 0
The correct answer is 21m

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Hey, Its the same person. This is Algebra 2. Please Help!
suter [353]

Answer:

first option

Step-by-step explanation:

Given

f(x) = \frac{2x^2+5x-12}{x+4} ← factorise the numerator

     = \frac{(x + 4)(2x-3)}{x+4} ← cancel (x + 4) on numerator/ denominator

     = 2x - 3

Cancelling (x + 4) creates a discontinuity ( a hole ) at x + 4 = 0, that is

x = - 4

Substitute x = - 4 into the simplified f(x) for y- coordinate

f(- 4) = 2(- 4) - 3 = - 8 - 3 = - 11

The discontinuity occurs at (- 4, - 11 )

To obtain the zero let f(x) = 0, that is

2x - 3 = 0 ⇒ 2x = 3 ⇒ x = \frac{3}{2}

There is a zero at ( \frac{3}{2}, 0 )

Thus

discontinuity at (- 4, - 11 ), zero at ( \frac{3}{2}, 0 )

7 0
3 years ago
What in trying to find is 95-3into4 3 for 4 times. 95-3x3x3x3=_____. What can i do for this answer. ‍☠️~_~-_- -_-||
Mandarinka [93]

Answer:

14

Step-by-step explanation:

To evaluate 95 minus 3, four times

95 - 3⁴

95 - (3 * 3 * 3 * 3)

95 - (81)

95 - 81

= 14

Hence, 95 - (3 * 3 * 3 * 3) = 14

6 0
3 years ago
Find the sum of 2.5+3.03
Alenkasestr [34]

Answer: 5.53


Step-by-step explanation:

this is a straight forward addition

2.5+3.03 =5.53

to be clear or to specify, use the decimal point to make the sum:

2.5 = 2 + 0.5       and 3.03 = 3 + 0.03

2+3= 5      and  0.5 + 0.03 = 0.53

5 + 0.53 = 5.53 (but this is to long just to make it clear)


5 0
3 years ago
Help please !!!!!!!!!!!!!!!!!!!
Dmitry [639]

Answer:

y=2x^2+1

Step-by-step explanation:

I checked on photo maths

3 0
3 years ago
Read 2 more answers
a train travels 304 miles in 4 hours if it continues to travel at the same rate how many miles will it travel in seven and a hal
svlad2 [7]

Answer:

570 miles

Step-by-step explanation:

304/4 is how many miles it travels in each hour and if its 7.5 hours then you multiply that by each mile it takes each hour.

304/4 = 76

76 x 7.5 = 570

5 0
3 years ago
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