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AfilCa [17]
3 years ago
9

If I have 17 boxes contain 23 chocolate bars each How many chocolate bars do I have in total?​

Mathematics
2 answers:
Nina [5.8K]3 years ago
8 0

Answer:

391 chocolate bars

Step-by-step explanation:

You just multiply 23 × 17!

Elenna [48]3 years ago
3 0

Answer:

391

Step-by-step explanation:

17 x 23 = 391

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This dude laughing hella
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Answer:

ok.......

Step-by-step explanation:

6 0
3 years ago
If using the method of completing the square to solve the quadratic equation x^2 + 3x +21 =0?
goldfiish [28.3K]

Answer:

x= \dfrac 12 \left( -3 +i5\sqrt 3\right)\\\\x= \dfrac 12 \left( -3 -i5\sqrt 3\right)

Step-by-step explanation:

~~~~~~x^2 +3x +21 = 0\\\\\implies x^2 +3x = -21\\\\\implies x^2 + 2\cdot  \dfrac 32 \cdot x + \left( \dfrac 32 \right)^2 = -21 + \left( \dfrac 32 \right)^2\\\\\implies \left(x + \dfrac 32 \right)^2 = -21+\dfrac 94\\\\\implies \left(x + \dfrac 32 \right)^2 = -\dfrac{75}4\\\\\implies x+ \dfrac 32 = \pm\sqrt{-\dfrac{75}4 \right)\\\\\implies x + \dfrac 32 = \pm i \dfrac{5\sqrt 3}{2}\\\\\implies x = -\dfrac 32 \pm i \dfrac {5\sqrt 3}2\\\\\implies x = \dfrac 12 \left( -3 \pm  i5\sqrt 3\right)

8 0
2 years ago
Dave bought some fresh produce. He picked up 2 oranges, and 3 bananas. The cost of the Dave's shopping was $9.16.
Helga [31]

Answer:prices = {"banana": 4, "apple": 2, "orange": 1.5, "pear": 3}

stock = {"banana": 6, "apple": 0, "orange": 32, "pear": 15}

for item in prices:

   print item + ":"

   print "price: " + str(prices[item])

   print "stock: " + str(stock[item])

Step-by-step explanation:

prices = {"banana": 4, "apple": 2, "orange": 1.5, "pear": 3}

stock = {"banana": 6, "apple": 0, "orange": 32, "pear": 15}

for item in prices:

   print item + ":"

   print "price: " + str(prices[item])

   print "stock: " + str(stock[item])

3 0
3 years ago
Assume that the business makes a profit with probability 0.8 in the first year. For each year thereafter, the business makes a p
Ivenika [448]

Answer:

The probability that the business makes a profit in exactly two of its first three years is 0.628.                          

Step-by-step explanation:

Given : Assume that the business makes a profit with probability 0.8 in the first year. For each year thereafter, the business makes a profit with probability 0.9 if it made a profit in the previous year, and with probability 0.2 if it did not make a profit in the previous year.

To find : What is the probability that the business makes a profit in exactly two of its first three years?

Solution :

Let X be the event that the business makes profit.

Y be the event that the business doesn't .

The business makes a profit with probability 0.8 in the first year.

For each year thereafter, the business makes a profit with probability 0.9.

It did not make a profit in the previous year is 0.2.

According to question,

The business makes a profit in exactly two of its first three years which is given by, XXY, XYX, YXX

So,

P(XXY)=0.8\times 0.9\times (1-0.2)

P(XXY)=0.8\times 0.9\times 0.8

P(XXY)=0.576

P(XYX)=0.8\times (1-0.9)\times 0.2

P(XYX)=0.8\times 0.1\times 0.2

P(XYX)=0.016

P(YXX)=(1-0.8)\times 0.9\times 0.2

P(YXX)=0.2\times 0.9\times 0.2

P(YXX)=0.036

The probability that the business makes a profit in exactly two of its first three years is given by,

P= P(XXY)+P(XYX)+P(YXX)

P= 0.576+0.016+0.036

P= 0.628

Therefore, The probability that the business makes a profit in exactly two of its first three years is 0.628.

= 0.272

7 0
3 years ago
Select the set or sets that the number below belongs to. Be sure to account for ALL sets. (Rational, Integer, Whole, Natural). T
arsen [322]

Answer:

rational interger whole and natural.

Step-by-step explanation:

It's all of them

5 0
3 years ago
Read 2 more answers
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