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steposvetlana [31]
3 years ago
14

Find the 7th term of the geometric sequence a3 =128,r=-1/4

Mathematics
1 answer:
kenny6666 [7]3 years ago
7 0

Answer:

Step-by-step explanation:

The general formula for this sequence is a(n) = a(1)*(-1/4)^(n - 1).  We don't yet know a(1).

If a(3) = 128, then 128 = a(1)*(-1/4)^(3 - 1), or

128 = a(1)*(1/16)

and so a(1) = 128/16

resulting in the specific formua a(n) = 8(-1/4)^(n - 1)

Now let's find a(7):

a(7) = 8(-1/4)^1 * (-1/4)^(6)

or

a(7) = 8(-1/4)^7

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A worker is paid $18.50 per hour for the first 40 hours of work and time and a half for any overtime exceeding 40 hours per week
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Answer:

The worker's pay is $795.50.

Step-by-step explanation:

The worker gets paid $18.50 for the first 40 hours of work. The worker works 46 hours. 18.50 • 40 = 740. He worked 6 hours overtime. $18.50 ÷ 2 = $9.25. $9.25 • 6 = $55.50.

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DF=78, DE=5x-9, and EF-2x+10, find EF
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Answer:

As e is point between df. So we can write df as

df = de + ef

As given df = 78 , de = 5x - 9 , ef = 2x + 10.

So we can write

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On subtracting 1 on booth side

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On dividing both side by 7.

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So x = 11.

So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32

Step-by-step explanation:

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Step-by-step explanation:

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