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3 years ago

Find the 7th term of the geometric sequence a3 =128,r=-1/4

Mathematics

1 answer:

kenny6666 [7]3 years ago

7 0

Answer:

Step-by-step explanation:

The general formula for this sequence is a(n) = a(1)*(-1/4)^(n - 1). We don't yet know a(1).

If a(3) = 128, then 128 = a(1)*(-1/4)^(3 - 1), or

128 = a(1)*(1/16)

and so a(1) = 128/16

resulting in the specific formua a(n) = 8(-1/4)^(n - 1)

Now let's find a(7):

a(7) = 8(-1/4)^1 * (-1/4)^(6)

a(7) = 8(-1/4)^7

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