Part A:
1) 16
2) -25
3) 9
4) -7
I'm too lazy to do the rest, just pay attention in class next time
Answer:
c = 27.9
B = 62.13°
C = 89.90°
Step-by-step explanation:
We are given the following values:
A= 121.59°, a = 27.9 cm, b = 52.6 cm
a) Finding side c
We would use Pythagoras Theorem
c² = a² + b²
c = √(a² + b²)
c = √(27.9² + 52.6²)
c = 59.54cm
≈ Approximately = 59.5cm
b) Finding B
We would be using Cosine rule to find Angle B
Cos B = a² + b² - c²/2ab
B = arc cos ( a² + c² - b²/2ac)
B = arc cos( 27.9² + 59.5² - 52.6²/ 2 × 27.9 × 59.5)
B = 62.13268°
B = 62.13°
c) Finding C
We would be using Cosine rule to find Angle C
Cos C = a² + b² - c²/2ab
C = arc cos ( a² + b² - c²/2ab)
C = arc cos( 27.9² + 52.6² - 59.5²/ 2 × 27.9 × 52.6)
C = 89.9°
Answer:
There is a 1/250 chance that his ticket will be chosen
There is a 249/250 chance that his ticket will not be chosen
Step-by-step explanation:
Hope that helps!
Answer:
(a) a=6 and b≠
(b)a≠6
(c) a=6 and b=
Step-by-step explanation:
writing equation in agumented matrix form
now 
now 
a) now for inconsistent
rank of augamented matrix ≠ rank of matrix
for that a=6 and b≠
b) for consistent w/ a unique solution
rank of augamented matrix = rank of matrix
a≠6
c) consistent w/ infinitely-many sol'ns
rank of augamented matrix = rank of matrix < no. of variable
for that condition
a=6 and b=[tex]\frac{11}{4}
then rank become 3 which is less than variable which is 4.
Answer:
49
Step-by-step explanation:
