Answer:
Step-by-step explanation:
f(x)-2=(-4-2)/(0-(-2))(x+2)
f(x)-2=-3(x+2)=-3x-6
f(x)=-3x-4
g(x)=3x-4
h(x)=-3x+4
j(x)-10=(22-10)/(6-2)(x-2)
j(x)=3(x-2)+10
or j(x)=3x+4
slope:-
f(x)=(-4-2)/(0-(-2))=-6/2=-3
g(x)=3
h(x)=(1-4)/(1-0)=-3
j(x)=(22-10)/(6-2)=12/4=3
y-intercepts:-
f(x)=-4
g(x)=-4
h(x)=4
j(x)=4
f(x) || h(x)
g(x) || j(x)
so they together represent a parallelogram.
Hello from MrBillDoesMath
Answer: + 4/7, 6 (13/14)
Discussion:
Let L be the larger of the two numbers and S the smaller of the two. Then the first sentence translates into this:
-6L - L = -4 =>
-7L = -4 => (divide both sides by -7)
L = - (-4)/(-7) = + 4/7 (*)
The second sentence translates to
2 (L + S) = 15 => (divide both sides by 2)
(L +S) = 15/2 => (subtract L from each side)
S = 15/2 - L = 15/2 - 4/7 (using (*) above)
So
S = 15*7/(2*7) - (4*2)/(7*2) (combine over common denominator of 14)
S = 105/14 - 8/14 = 97/14 = 6 13/14
Something is crazy here! While 2(L +S) = 15 -- check it out -- our larger number L ( =4/7) is actually smaller than the S number (6 13/14)! Maybe I should have called them Y and X, respectively, as you suggested!
Thank you,
Mr. B
Answer:
Step-by-step explanation:
a.
first number is 1000-1+9=1008
9)1000(1
9
-------
10
9
-----
10
9
----
1
----
last number is 9999
9| 9999
---------
1111 |0
--------
9999=1008+(n-1)9
9999-1008=(n-1)9
n-1=8991/9=999
n=999+1=1000
b.
first digit=1000
last digit=9999-1=9998
2 |9999
---------
|4999|1
9998=1000+(n-1)2
(n-1)2=9998-1000=8998
n-1=4499
n=4499=1=5000
c.not sure
d.
total numbers=9000
9999=1000+(n-1)1
9999-1000=n-1
n=8999+1=9000
numbers divisible by 3=3000
first number=1002
last number=9999
9999=1002+(n-1)3
(n-1)3=9999-1002=8997
n-1=2999
n=2999+1=3000
numbers not divisible by 3=9000-3000=6000
e.
numbers divisible by 5=1800
first number=1000
last number=9995
9995=1000+(n-1)5
(n-1)5=9995-1000=8995
n-1=1799
n=1799+1=1800
numbers divisible by 7=1286
7 | 1000
---------
| 142-6
1000-6+7=1001
7 | 9999
|---------
1428-3
9999-3=9996
first digit=1001
last digit=9996
9996=1001+(n-1)7
(n-1)7=9996-1001=8995
n-1=1285
n=1285+1=1286
numbers divisible by 35=257
first digit=1015
35 ) 1000 ( 28
70
----
300
280
------
20
---
1000-20+35=1015
35)9999(285
70
----
299
280
-----
199
175
----
24
----
last digit=9999-24=9975
9975=1015+(n-1)35
(n-1)35=9975-1015=8960
n-1=8960/35=256
n=257
reqd. numbers=1800+1286-257=3019
Answer:
x ∈ (-oo ; 3)
Step-by-step explanation:
4x - 7 < 5
4x < 5 + 7
4x < 12
x < 12 : 4
x < 3
x ∈ (-oo ; 3)
