Answer:
![200 + 0.07m \leq 230](https://tex.z-dn.net/?f=200%20%2B%200.07m%20%5Cleq%20230)
A maximum of
428 miles is the distance what Divya can travel.
Step-by-step explanation:
Given that:
Rent to be paid for the car in the weekend = $200
Charges to be paid per mile = $0.07
Total money available with Divya = $230
To find:
The inequality as per her limitations and solution to the problem.
Solution:
Let the number of miles for which Divya can drive =
miles
Charges for one mile = $0.07
Charges for
miles = $0.07![m](https://tex.z-dn.net/?f=m)
Total charges for renting and
miles = Rental charges + Operational charges
Total charges for renting and
miles = $200 + $0.07![m](https://tex.z-dn.net/?f=m)
These are charges must be lesser than equal to the amount of money available with Divya.
Therefore, we can write:
![200 + 0.07m \leq 230](https://tex.z-dn.net/?f=200%20%2B%200.07m%20%5Cleq%20230)
Subtracting 200 from both the sides:
![0.07m \leq 30](https://tex.z-dn.net/?f=0.07m%20%5Cleq%2030)
Dividing both sides with 0.07:
![m \leq \dfrac{30}{0.07}\\m\leq 428.6](https://tex.z-dn.net/?f=m%20%5Cleq%20%5Cdfrac%7B30%7D%7B0.07%7D%5C%5Cm%5Cleq%20428.6)
Therefore, a maximum of
428 miles is the distance what Divya can travel.