First, factor out a 3.
3(x² - 9)
In any quadratic ax² + bx + c, we can split the bx term up into two new terms which we want to equal the product of a and c.
In this case, we have x² + 0x - 9. (the 0x is a placeholder)
We want two numbers that add to 0 and multiply to get -9.
Obviously, these numbers are 3 and -3.
Now we have 3(x² + 3x - 3x - 9).
Let's factor.
3(x(x+3)-3(x+3))
<u>3(x-3)(x+3)</u>
There are multiple shortcuts which you could make here, FYI:
Instead of splitting the middle, if your a value is 1, you can go straight to that step (x+number)(x+other number).
Whenever you have a difference of squares, like a²-b², that factors to (a+b)(a-b).
If a< c< b then a<c and c<b
Separate the equation into 2 separate ones and solve them:
X-9 < 4x +3
Subtract 3 from both sides:
X-12 < 4x
Subtract x from both sides:
-12< 3x
Divide both sides by 3:
X > -4
4x+3 < 27
Subtract 3 from both sides
4x < 24
Divide both sides by 4
X <6
Combine to get one inequality:
-4<x<6
Answer:
900 calories
Step-by-step explanation:
First you have to find the unit rate, how many calories are there in ONE cracker? To find that you have to divide 60 ÷ 12 = 5 and to check with the other one, 75 ÷ 15 = 5
So, one cracker is 5 calories. Now, how many calories are in 180 crackers? You multiply, 180 x 5 = 900
That means there are 900 calories in 180 crackers.
Hope that helps and have a great day!
Answer:
8.06
Step-by-step explanation:
√(x2 - x1)² + (y2 - y1)²
√(6 - 2)² + (0 - 7)²
√(4)² + (-7)²
√(16) + (49)
√65
= 8.06
